> This points to an interesting observation. A single real photon ALL BY
> ITSELF cannot pair-produce, for *exactly* the reason you just cited.
> (A virtual photon can, because it can have nonzero rest mass.) Pair
> production occurs in the presence of another charged object.
I stated it a little too strong. In theory, two photons with equal
energy moving in opposite directions can collide and form an electron-
positron pair even in a vacuum. I say "in theory" because the cross
sectional area for this reaction is extremely small.
One can calculate the cross section for the "two photon
annihilation and pair production" using quantum electrodynamics.
However, it is far too small to to determine with current technology.
That is why I listed some other reactions that have been validated
with experiment, and address his implied question.
He was asking whether the reverse effect happens. The QED theory
predicts that the answer is "yes" but experiments to prove it are
impractical at present.
His more-general implied-question was whether particles with
zero rest mass could annihilate to form particles with positive rest
mass. There are reactions like this that are not only predicted by
QED, but have been detected experimentally. So I listed some reactions
that have been experimentally verified.
I suspect that photon annihilating photon reactions occurred when
the density of photons and electron-hole pairs was much larger. There
may have been a time a few short moments after the Big Bang when such
reactions were likely. However, I doubt whether there are any
astronomical observations that could support this.
The reaction of electron-hole pairs, or even mesons, in a
proton-proton collision are enough to prove that "invariant mass" can
be created from kinetic energy. Of course, relativistic mass is
equivalent to total energy. However, I think the concept of
"relativistic mass" has a certain heuristic value.
>And in
> that closed system, you find that invariant mass *is* conserved but it
> is the invariant mass of the WHOLE SYSTEM.
>
> And remember, a two-photon system (for example) can have nonzero
> invariant mass, even though the individual photons each have zero
> invariant mass.
Yes, they do. That is one reason that I think that relativistic
mass should be kept as a broad concept. A sealed box of photons is
"heavier" because it contains photons, even though each photon has no
rest mass. The sealed box has additional inertial mass when it traps
photons. The sealed box has extra inertial mass if the electrons in
the box are moving at high speed. So the energy trapped in the box can
be considered as contributing to the total inertial mass.
Good question.
Maybe an electron is created when a photon makes something in the aether spin?
The photon's energy is now manifest in the electron's spin?
This makes me think a little along the lines of mass/time.
Take a spherical particle, mass = m, orbiting something. It sweeps out a volume (ring) every revolution. As it's
speed approaches infinity, it is as though the particle is everywhere in that ring simultaneously. So the mass is the
density of the particle * ring volume.
Obviously, as the speed increases, the orbit would typically increase so.................
> Good question.
>
> Maybe an electron is created when a photon makes something in the aether spin?
>
> The photon's energy is now manifest in the electron's spin?
So now that you are thinking ponder this sort of model. Suppose and
electron is some kind of spinning vortex in the aether. Suppose that
positron is the same vortex only spinning the other direction.
So what happens when those two items collide? Well one thing that COULD
happen would be like having two flywheels connected like a Yo Yo
spinning in opposite directions and you apply brakes between them. Spins
disappear and heat (EM radiation) is emitted. So we could think of a
model like this for matter-antimatter annihilation.
But wait. If we have a photon buzzing along alone it seems that we can
split it in the thing called "pair production" back into an electron and
a positron. So does this not say that flywheel-brake model is wrong. The
two spinning objects must keep spinning in the photon, because later if
they were stopped, you'd have to propose some sort of spin-up mechanism
to get them going again for pair production! It's simpler (Occam's
razor) to simply propose that photons are composed ot two spinning
particles whose spin effects cancel at a distance. However close to the
photon that might not be the case!
Food for thought.
How could we have observed a light wave become matter?
Compton says light energy can push matter faster not
that it can convert. Please show the measurements of
this phenomenon happeing. It is just a poor notion that
we have.
Positrons can't make it in the earth's atmosphere.
We have only matter to store anti matter but they
would react right on the spot. The anti matter debacle
is also a big emberassment to a science that thought
it knew what it was talking about.
>
> How could we have observed a light wave become matter?
> Compton says light energy can push matter faster not
> that it can convert. Please show the measurements of
> this phenomenon happeing. It is just a poor notion that
> we have.
http://teachers.web.cern.ch/teachers/archiv/HST2002/Bubblech/mbitu/electron-positron.htm
>On Oct 11, 2:54 pm, PD <thedraperfam...@gmail.com> wrote:
>> On 10/11/2011 4:35 PM, jon car wrote:
>>
>> > How could we have observed a light wave become matter?
>> > Compton says light energy can push matter faster not
>> > that it can convert. Please show the measurements of
>> > this phenomenon happeing. It is just a poor notion that
>> > we have.
>>
>> http://teachers.web.cern.ch/teachers/archiv/HST2002/Bubblech/mbitu/el...
>That is funny. A track? Where did we get the original positron from?
In the first photo they are from pair production, see the original
question. A high energy photon becomes an electron-positron pair.
In the second photo, the source of the first isn't specified but it's
probably from a high energy collision. It annihilates and the photon
created produces an electron-positron pair, the second positron.
>What much can that track tell you seriously?
Bubble chambers create a track when a charged particle passes through
them. Think of the tracks as "footprints" of the particle.
Add a magnetic field and the tracks will curve, and you can tell
the charge (by which way they curve) and the charge-mass ratio (by how
much they curve).
Bubble chambers are very old technology. Cloud chambers (similar idea)
are even older, amateurs have built them.
>I believe there is more like 12 fundamental particles.
Nobody cares what you believe. Science is about what can be measured.
Positrons have been measured.
>We are fooling ourselves about what we know by a bubble chamber guess.
It's not a guess, it's a measurement.
>If that's all we have?
No. Technology has come a long way since the 1950s, and there are much
more advanced ways to measure such things.
>Good luck!
Ever eat a banana? You got a mouthful of positrons from it from the
potassium-40 in them.
>Anti matter can't be contained with anything but itself. It is ruled
>out bacsuse it would have to be handled by real matter and that means
>anihilation.
Look at bubble chamber pictures and you'll see they don't last very long
before they find an electron to annihilate with.
What is measured then?
> >If that's all we have?
>
> No. Technology has come a long way since the 1950s, and there are much
> more advanced ways to measure such things.
>
> >Good luck!
>
> Ever eat a banana? You got a mouthful of positrons from it from the
> potassium-40 in them.
>
> >Anti matter can't be contained with anything but itself. It is ruled
> >out bacsuse it would have to be handled by real matter and that means
> >anihilation.
>
> Look at bubble chamber pictures and you'll see they don't last very long
> before they find an electron to annihilate with.
You are bananas. There is no anti matter in a banana.
How could it hide itself in potassium?
I doubt that. What is a bubble chamber trails left behind composed of?
The tracks? how mant measurements could they perform?
No. We are set up to fool ourself if we think we are going beyond
just guesses.
> >We are fooling ourselves about what we know by a bubble chamber guess.
>
> It's not a guess, it's a measurement.
>
> >If that's all we have?
>
> No. Technology has come a long way since the 1950s, and there are much
> more advanced ways to measure such things.
Technology doesn't make anyone smart. It for your entertainment
system!
> >Good luck!
>
> Ever eat a banana? You got a mouthful of positrons from it from the
> potassium-40 in them.
>
> >Anti matter can't be contained with anything but itself. It is ruled
> >out bacsuse it would have to be handled by real matter and that means
> >anihilation.
>
> Look at bubble chamber pictures and you'll see they don't last very long
> before they find an electron to annihilate with.
Where again do positrons come from?
they create NONZERO MASS
do you listen that you say ??
you create non Zero mass from zero mass
can mass be created from nothing !!??
------------------
2
E=hf is the energy of photon
WHERE AT ALL YOU SEE MASS IN IT
3
IF SO
WHERE DO YOU SEE *RELATIVISTIC MASS*
IN THE ABOVE FORMULA
----------------
> Yes, they do. That is one reason that I think that relativistic
> mass should be kept as a broad concept.
--------------
what is a'' broad concept'' ??
broad for what
that anyone will be able so say whatever he likes about it
are we in a philosophy NG
or lawyers tactics business ??
or in an accurate definite science
A sealed box of photons is
> "heavier" because it contains photons, even though each photon has no
> rest mass. The sealed box has additional inertial mass when it traps
> photons. The sealed box has extra inertial mass if the electrons in
> the box are moving at high speed. So the energy trapped in the box can
> be considered as contributing to the total inertial mass.
-================================-----
where in
E=hf
you see ANYTHING RELATIVISTIC ??!!
TIA
Y.Porat
------------------------------
The mass comes from the *conversion* of energy TO mass.
Most measurements of what is considered important are tailored; some
to the truth.
Mitchell Raemsch
You can look up how bubble chambers work. Particles ionize the liquid
as they pass through it. Releasing pressure on the liquid causes it to
boil, and boiling occurs where there are nucleation sites first. This
happens where there is ionization. It's a very well established
technology.
Porat, you're going to have to get used to the idea that some people
have other things to do during the day.
What then is stealing electron's for these ions? and where do they go
then?
Mitchell Raemsch
They are knocked out of the atoms of the liquid by the passing
particle. That's what ionizing MEANS.
>
> Mitchell Raemsch
NOW YOU TALK ABOUT A LUMP OF ENERGY
why a lump ?? who dont you say as in your past
that it is a single smallest photon energy ?
it seems that you did some adavnce
yet not good enough and not cleaver enough to admit
who made that little change in your understanding
yet
it is still not good enough
so
let me ask you a few silly questions:
you say it is emitted ''AT ONCE''
so we are going to see about your
'AT ONCE' ...
now
leat take two cases:
case 1
a photon energy E=hf1
is emitted on an electric cell
for along **one second
case 2
the same photon energy E=hf1 is
emitted on the above same cell
for two seconds
my question is
in which of the above cases
more electrons will bee mitted from that cell
in case1
or in case 2 ??
2
**how much **quantitatively** more
will it be in case 2
--------
3
dont impress us about your being busy
in order of not answering a few simple questions
we can all of us notice that you sit
most of your time next to the computer
as if it was your income job ....
th e number of your responses
too '' various'' people tell it .
TIA
Y.Porat
-----------------------
------------------
SO (:-)
i asked you from where does
ENERGY (Enrgy )
takes it s mass ??
you say 'relativistic mass??
so
1
were do you at all see
ANY mass in
hf ??
2
what in E=hf
IS RELATIVISTIC ???
if you are to busy
i dont mind if you take your time to answer
yet please after all
answer honestly
TIA
Y.Porat
-------------..
TIA
Y.Porat
-------------------------
------------
How do they unbond from the atom surface? What angle to the passing
particle strike and undo the bond? What is the dynamics of the
unbonding?
Does it take a weight? motion level?
There is new physics to be done. What is unbonding?
> particle. That's what ionizing MEANS.
>
>
>
>
>
> > Mitchell Raemsch- Hide quoted text -
>
> - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
Mitchell Raemsch
It doesn't need to find mass somewhere to make mass. Energy *becomes* mass.
>
> you say 'relativistic mass??
No, I did not say that. This is YOUR favorite whipping boy. I don't use
the term myself.
It isn't done in a continuous process for 1 second. It is delivered ALL
AT ONCE.
That means that if a *single* photon is received at a receiver, it will
not matter whether you look at that receiver for 1 second or 100 seconds
or 0.0000000001 seconds, the amount of energy delivered by that single
photon will be the same -- that same small lump.
Now, I know you get confused and you say that sunlight shining on a car
will deliver twice as much energy in 2 seconds than it will in one
second. Do you know the difference between a photon and a stream of photons?
Let me put it to you this way, Porat:
If I tell you to pour water out of a hose into a bucket, then you will
get twice as much water in the bucket in two minutes compared with what
you get in one minute.
But if I tell you to put ONE DROP of water in the bucket, will it matter
if you wait one minute or two minutes or thirty minutes? No, you will
still have ONE drop.
Sorry, so far all your questions are not new physics. They are OLD
physics, which you have yet to learn.
http://pdg.lbl.gov/2011/reviews/rpp2011-rev-passage-particles-matter.pdf
i asked you about experimental facts
i gave you case 1
and case 2
and asked you
will the **number** of electrons emitted from that photoelectric
cell
in case 1
will be the same inboth cases
2
if ther will be a change
can we say that in case of two seconds
the number of electrons will be
2 times more than in case 1??
please answer that
and we dont need and i intentially didnt ask your interpretaions about
how and why !!
(to be frank
in order o f not letting you to obfuscate the simple question
(ther will be room for interpretations
only at the nest stage !!)
so please answer my above
two cases question as experimental facts or expeimental experience
2
now if your right answer (imho )
will be
in case 2 there will be practically
two times more electrons emitted that case of one second
right ??
-------------------
> That means that if a *single* photon is received at a receiver, it will
> not matter whether you look at that receiver for 1 second or 100 seconds
> or 0.0000000001
----------
you forget a simple fact !!
if a photon is acting by E+hf1 only for one second
(ON A PHOTOELECTRIC CELL)
you wilL not detect **after** one second
ANY MORE ELECTRON EMITTED
AND THE SAME
if it will be acted by E=hf1 only for Exp -9 second
after say much less than half a second
you will NOT detect **any additional electrons emotion !!!**
so please dont let nonsense
and dont try to obfuscate the above
****simple*** question
TIA
Y.Porat
-----------------------
They will be the SAME! Correction: They ARE the same, observationally.
There is only one energy deposit by a single photon in both cases. There
will only be one photoelectron emitted in both cases.
> 2
> if ther will be a change
> can we say that in case of two seconds
> the number of electrons will be
> 2 times more than in case 1??
No.
>
> please answer that
> and we dont need and i intentially didnt ask your interpretaions about
> how and why !!
> (to be frank
> in order o f not letting you to obfuscate the simple question
> (ther will be room for interpretations
> only at the nest stage !!)
> so please answer my above
> two cases question as experimental facts or expeimental experience
> 2
> now if your right answer (imho )
> will be
> in case 2 there will be practically
> two times more electrons emitted that case of one second
> right ??
No. That is wrong.
It is just like one drop of water in the bucket. It doesn't matter
whether you sit there for a minute or two minutes. There will still be
ONE drop of water in the bucket.
while the photon E=hf1
is active during two seconds on an electric cell
th excell will be emitting electrons for two seconds
you AND EVRY ONE can do THST SIMPLE EXPERIMENT IN HOME CONDITIONS !
take a lead torch keep it lited during
one of two seconds onsay
a pochet calculatir opperated by a
phootn electric cell
th calcuators digits will be seen for two seconds
but after two sconds it will be turned of
and you will not see the digits there
THE SAME WILL BE IF YOU LIGHT THE CELL FOR *HALF A SECOND!!
GOT IT armchair MUMBLER --
---->EVEN FOR HALF A SECOND !!!
the calculator will be turned off
***only ** after
half a second !!
ie
compatible with **duration **of light emission on it !!
-------
so just do it
it needs a proper light wave length
ie
the background light must be
with 'yellow' light
ie bigger wave length than the Led light !!...
and dont boggle our balls with idiotic
guesses !!
there is experimental data !!!
it is historically important by its meaning
and revolutionary important !!
TIA
Y.Porat
---------------------
> --------------
> idiotic wrong obfuscation answer !!
>
> while the photon E=hf1
> is active during two seconds on an electric cell
> th excell will be emitting electrons for two seconds
> you AND EVRY ONE can do THST SIMPLE EXPERIMENT IN HOME CONDITIONS !
No, Porat, that is NOT what's going on.
If you have a STREAM of photons on a electric cell, then you will have
twice as many electrons emitted in two seconds as you do in one second.
But if you have ONE photon hitting an electric cell, you will get
exactly the same number of electrons emitted in two seconds as you do in
one second.
You confuse a STREAM of photons with a SINGLE photon.
A stream of water is not a drop of water.
How about SN2006gy? Thought to have been caused when a very massive
star's core got so hot, gamma rays spontaneously converted into
electron-positron pairs that, being massive, were much slower than the
photons and exerted less pressure, so the star suddenly could not
support itself against its gravity anymore, leading to the star's core
imploding.
If it occurred in a sufficiently hot stellar core, it would presumably
also have occurred shortly after the bang during the period when the
cosmic temperature was comparable.
[...]
I like how Porat can still manage to not understand physics that is older
than he is.
Not at all. They are questions we need to revisit. They are unfinished
bussiness.
If you think we are far along with anything you have something
comming.
>
> http://pdg.lbl.gov/2011/reviews/rpp2011-rev-passage-particles-matter.pdf
>
>
>
>
>
> >> particle. That's what ionizing MEANS.
>
> >>> Mitchell Raemsch- Hide quoted text -
>
> >> - Show quoted text -- Hide quoted text -
>
> >> - Show quoted text -
>
> > Mitchell Raemsch- Hide quoted text -
>
> - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
Mitcell Raemsch
>On Oct 13, 6:18 am, PD <thedraperfam...@gmail.com> wrote:
>> On 10/12/2011 10:08 PM, jon car wrote:
>> > There is new physics to be done. What is unbonding?
>>
>> Sorry, so far all your questions are not new physics. They are OLD
>> physics, which you have yet to learn.
>Not at all. They are questions we need to revisit. They are unfinished
>bussiness.
No, this is OLD stuff, known for decades. A highly energetic charged
particle passing through matter will disrupt electrons in the matter as
it passes, leaving a trail of ions. This is how radioactive substances
damage living things, the alpha and beta particles ionize things like
DNA.
What do you mean highly energetic? Qualify that.
Why would ONLY an ionic state emit light for us to see in the trail?
Study up. You need to be smart if you want to pass the first test!
A single photon? Einstein saw photons going in a certain size packets.
Called "quanta" Maybe a single photon can go to a low energy
electron? I read that what we consider a single photon can go through
a million holes at once. We now know an electron is not a point but a
cloud.Hmmmm That means an atom's nucleus is inside a negatively
charge cloud. Might just call this cloud a "field" That answers some
hard questions TreBert
Einstein doubted his photon. In 1937 he said he could never finally
reconcile the wave and particle together. I think he was right to
question what he even won the Nobel prize for. Some Nobel prizes might
go in reverse based on our state of knowledge by the truth.
Mitchell Raemsch
I sort of disagree.
It seems other matter is always needed for pair creation - why? Matter seems to act as a catalyst.
I believe the energy can create pressure and spin to condense/spin something out of the aether.
itis the question of
is he light WE SEE AND MEASURE
DURING MORE THAN A FRACTION OF SECOND
A STREAM OF PHOOTNS
OR A SINGLE PHOTONS CASE
MY CLAIME IS THAT
TH EVERY FACT WE CAN MEASURE OR EVEN NOTICE
ANY LIGHT
**THAT IS FOR ITSELF
again for itself
THEPROVE THAT IT IS A ***STREAM OF PHOTON PARTICLE UNITS **
AGAIN
***A STREAM** ***A
continuous STREAM OF PHOTON UNITS**
AND NOT
SINGLE PHOTONS emission PHENOMENON !!!
> A stream of water is not a drop of water.
-------------
exactly !!
yet as above
our case of seeing light even for a fraction of a second
IS it A STREAM OF PHOTON UNITS
AND NOT A DROP OF DROPS TO
YOUR BUCKET EXAMPLE !!
and i can give you even a much simper example
take a light torch
lite it on in two cases :
case 1
lightit on for 1/second and imediatelt afterthat turn it of
case 2
take THE SAME TORCH!!
light it on untill AND AS LONG AS
ITS BATTERY IS OFF
question
IN WHICH CASE MORE PHOTON ENERGY WILL BE EMITTED
in case 1
or in case 2
PLEASE NOTE THAT IN CASE 1
THE TORCH WAS ACTIVE ONLY
1/10 OF A SECOND !!
so what is your answer
until that point ?
now we go furtherin a following
the abovet rivial experiments
moe general question
is emission of light ENERGY -
TIME DEPENDENT OR NOT ??!!
TIA
Y.Porat
------------------------
-------------
(:-)
the crippled retarded PD's ass leeker
opened its mug
(:-)
Y.P
------------------------
Y.P
According to QM we only generate astronomical amounts of light waves
to be measured statistically. Einstein could explain why a statistical
theory was the lowest form. He would not go along with it unless
science demanded it. And that's what they did.
"Science knows only the odds. While God knows every outcome." Mitchell
Raemsch
>On Oct 13, 5:15 pm, moro...@world.std.spaamtrap.com (Michael Moroney)
>wrote:
>> >> Sorry, so far all your questions are not new physics. They are OLD
>> >> physics, which you have yet to learn.
>> >Not at all. They are questions we need to revisit. They are unfinished
>> >bussiness.
>>
>> No, this is OLD stuff, known for decades. A highly energetic charged
>> particle passing through matter will disrupt electrons in the matter as
>> it passes, leaving a trail of ions. This is how radioactive substances
>> damage living things, the alpha and beta particles ionize things like
>> DNA.
>What do you mean highly energetic? Qualify that.
Kinetic energy substantially more than the ionization energy (typically a
couple of eV). Particles whose energy is measured in keV, or MeV levels.
>Why would ONLY an ionic state emit light for us to see in the trail?
Bubbles don't "emit light". Read up on nucleation to read why they form.
>Study up. You need to be smart if you want to pass the first test!
I don't know WTF you are talking about.
My banana supply is comming in shipments.
Anti matter goes to pure energy!
I will either that or go solar michael.
> substantially more than the ionization energy (typically a
> couple of eV). Particles whose energy is measured in keV, or MeV levels.
What is the name of the particle?
> >Why would ONLY an ionic state emit light for us to see in the trail?
>
> Bubbles don't "emit light".
What is lighting up the bubble track? You claimed bubbles.
No. You do not know what you are talking about.
And so you clearly do not know about detectors that can detect SINGLE
PHOTONS, not electric cells.
Electric cells can detect streams but not single photons. You CAN
detect single photons with appropriate detectors.
Because you can't conserve momentum AND energy otherwise. Do the
calculations. You'll see.
>On Oct 13, 6:16 pm, moro...@world.std.spaamtrap.com (Michael Moroney)
>wrote:
>> >What do you mean highly energetic? Qualify that.
>>
>> Kinetic energy
>How fast?
The more energetic ones will be moving close to c.
The less energetic ones a small fraction of c.
>> substantially more than the ionization energy (typically a
>> couple of eV). Particles whose energy is measured in keV, or MeV levels.
>What is the name of the particle?
It depends on the experiment. The images that started this goofy
subthread show electrons and positrons.
>> >Why would ONLY an ionic state emit light for us to see in the trail?
>>
>> Bubbles don't "emit light".
>What is lighting up the bubble track? You claimed bubbles.
A light bulb? The flash bulb of a camera (triggered to the expansion
piston) ? Someone who knows the design details better than I will have to
answer this.
-------------
and that s another proof that you are
an idiot crook demagogue
so actually BTW
smarty i new you might say that
but still that is stupidity and ignorance
so smarty i will ask you that in another way :
take the above experiment
light a** laser** torch that has only one wave length
and light tt withe very same torch
in identical conditions except one variable
ie time :
case 1
for 1/10 second
case 2
light it
all the way long untill its battery is of power
my question is :
IN WHICH CASE
MORE ***PHOTON ENERGY***WILL BE EMITTED
IN CASE 1
OR IN CASE 2
TIA
Y.Porat
----------------------
This conversation suggests to me a conversation between a young,
impertinent pygmy who has never left his village with an astronaut
that landed off track in the jungle, debating the existence of space
vehicles.
Very amusing.
Uncle Ben
Very amusing.
Uncle Ben
===========================================
You are not young, Bonehead. Impertinent and a pygmy, yes, never
left the backwoods of NewYork State, yes, but young does not describe
you at all.
A laser torch provides a STREAM of photons.
What you need is a source of SINGLE photons.
Stop talking about photon-stream detectors like electric cells, and
photon-stream producers like lasers, and start talking about
SINGLE-PHOTON sources and SINGLE-PHOTON detectors.
>>
>>>> They are knocked out of the atoms of the liquid by the passing
>>
>>> How do they unbond from the atom surface? What angle to the passing
>>> particle strike and undo the bond? What is the dynamics of the
>>> unbonding?
>>> Does it take a weight? motion level?
>>
>>> There is new physics to be done. What is unbonding?
>>
>> Sorry, so far all your questions are not new physics. They are OLD
>> physics, which you have yet to learn.
>
> Not at all. They are questions we need to revisit. They are unfinished
> bussiness.
Then revisit them yourself. Most other people have moved on, this being
established and old physics. Just because YOU have yet to learn it,
doesn't mean that everyone else needs to be on the same boat you're in.
>
>>> Why would ONLY an ionic state emit light for us to see in the trail?
>>
>> Bubbles don't "emit light".
>
> What is lighting up the bubble track? You claimed bubbles.
A lamp inside the bubble chamber. Seriously.
Do you know how to google "bubble chamber"?
> Uncle Ben
>
> ===========================================
> You are not young, Bonehead. Impertinent and a pygmy, yes, never
> left the backwoods of NewYork State, yes, but young does not describe
> you at all.- Hide quoted text -
>
> - Show quoted text -
By crackee, you got me there, you young whipper-snapper, I am indeed
not young. And you may be pleased to note that I have often been
granted admission to the UK and have learned to appreciate your best
bitter as a perquisite to persons in your country.
As for you, I have been tempted to write an essay about the different
kinds of annoying persons who post in this newsgroupt. Usually I
ignore them, but it occured to me that there are two important scales
by which to measure them.
Take Dono, for example (aka Adrian Sfarti, computer scientist,
Sunnyvale, CA, USA). His principal characteristic is arrogance. He
knows just enough SR to make a fool of himelf, but he assumes the
mantle of expert, offering to educate me in the fundamentals of
physics. While I am certainly willing to learn from anyone qualified
to teach me something, his "efforts" are merely absurd.
As for you, you certainly outdo Dono in arrogance, since you think you
have uncovered an algebraic error or two in Einstein's 1905 relativity
paper, although your explanations are based on an elementary confusion
of FORs.
As for integrity, Dono has the annoying habit of changing his argument
(when confronted with proof of its absurdity) and then pretending that
he never said the absurd version at all.
An example in this thread is that when discussing the relativistic
phenomenon of a speeding rod's length, he first asserted that the
change of length depends on which end of the rod is the point of
application of a force. When corrected, he developed the idea that the
length of the rod depends only on its velocity, not its acceleration,
which is true, but he pretends that he never committed his former
error.
That is a lack of integrity. It is not a moral error to make a
mistake, but it is a moral error to lie about it. He has done that
with me before.
In your case, I have caught you only in one outright lie of any
importance: that you have a Ph.D. in mathematics. The lie is obvious
to any reader with even an undergraduate degree in mathematics, so I
do not need to quote the evidence.
Although you are generous with your insults as to integrity, you
cannot quote any lie of mine, aside from my teasing you occasionally
about being gay. In physics, I may make mistakes, but when I am shown
them, I confess and thank my teacher.
As for your knowledge of physics, you have the typical narrowness of
an autodidact. You know a lot about certain things, but you often
wander beyond your proper bounds and, like Dono, make a fool of
yourself. You have a weakness in that you cannot accept any
correction; you are completely ineducable, no matter how clever the
attempt to inform you.
So, on we go in the SPR funhouse, enjoying the amusements, learning
things occasionally from the real experts, and marvelling at the
psychopathology.
Uncle Ben
Dono's flip-flop was not in this thread but in the thread about length
contraction. The thread is just now slowing in its growth rate and
maybe is terminating.
> Uncle Ben
>
> ===========================================
> You are not young, Bonehead. Impertinent and a pygmy, yes, never
> left the backwoods of NewYork State, yes, but young does not describe
> you at all.- Hide quoted text -
>
> - Show quoted text -
By crackee, you got me there, you young whipper-snapper, I am indeed
not young. And you may be pleased to note that I have often been
granted admission to the UK and have learned to appreciate your best
bitter as a perquisite to persons in your country.
===========================================
We are a kindly folk, we lay down the welcome mat to all. Unfortunately
the wogs (worthy oriental gentlemen) set up their mosques here and try
to change our way of life to theirs. But as you are only 6 hours away
and a redneck without any integrity, your short excursions into our green
and pleasant land to have a pint next door hardly counts as leaving your
village .
As for you, I have been tempted to write an essay about the different
kinds of annoying persons who post in this newsgroupt. Usually I
ignore them, but it occured to me that there are two important scales
by which to measure them.
Take Dono, for example (aka Adrian Sfarti, computer scientist,
Sunnyvale, CA, USA). His principal characteristic is arrogance. He
knows just enough SR to make a fool of himelf, but he assumes the
mantle of expert, offering to educate me in the fundamentals of
physics. While I am certainly willing to learn from anyone qualified
to teach me something, his "efforts" are merely absurd.
As for you, you certainly outdo Dono in arrogance, since you think you
have uncovered an algebraic error or two in Einstein's 1905 relativity
paper, although your explanations are based on an elementary confusion
of FORs.
==============================================
Arrogance? Ha! You are the fuckwitted faggot that boasted:
"If you want to know where I got my Ph D., look me up in American Men of
Science. I am not interested in being interrogated by an ignorant,
undisciplined, boor like you. Mental illness is no excuse." - Bonehead
Green Jr. Ph.D. physics 1956 Johns Hopkins "American Man of Science"
I didn't ask to know where you got your phrenology degree, Bonehead.
I may be arrogant, I may be undisciplined, I may even be a boor, but
I'm far from ignorant.
As for algebraic error, upsilon = xi/tau which you have no answer to,
being mentally ill and lacking the integrity of an intellectual pygmy as
you do.
As for integrity, Dono
=======================
I don't give a flying fuck about Dono, he's a shithead like you.
I only want to piss off an arrogant mentally ill intellectual pygmy
and integrity-less boor that can't fathom upsilon = xi/tau <> v = x/t.
"c+v is not the speed of anything w.r.t. anything" -- Bonehead Green, pygmy
redneck.
Who would imagine that this simple law [constancy of the velocity of
light] has plunged the conscientiously thoughtful physicist into the
greatest intellectual difficulties? -Chap. VII. Albert Einstein
Run away, cowardly Bonehead, like you always do.
=================================================
Talking to yourself again, Bonehead? Mentally ill is no excuse.
Atoms are not more energetic they are more massive by motion.
How have these speeds been measured and what is the cause of that fast
motion through the chamber?
I say they are not. Atoms are not energetic they just have different
sizes. They can expand under heat.
What about the atom qualifies it as energetic?
> The less energetic ones a small fraction of c.
>
> >> substantially more than the ionization energy (typically a
> >> couple of eV). Particles whose energy is measured in keV, or MeV levels.
> >What is the name of the particle?
>
> It depends on the experiment. The images that started this goofy
> subthread show electrons and positrons.
>
> >> >Why would ONLY an ionic state emit light for us to see in the trail?
>
> >> Bubbles don't "emit light".
> >What is lighting up the bubble track? You claimed bubbles.
>
> A light bulb?
The bulb is lighting up what? What blows the bubbles all along the
way?
How does a subatomic particle blow bubbles by striking subatomic
electrons?
Mitchell Raemsch