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mean free path and fusion in tesla coil

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Chris

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Oct 13, 2008, 6:53:32 PM10/13/08

mean free path and fusion in tesla coil

Calculation of pressure required at various potential gradients
Mean Free Path
Vacuum rangePressure in hPa (mbar)Molecules / cm3Molecules m-3mean free path
Ambient pressure10132.7*10192.7*102568 nm
Low vacuum300-11019-10161025-10220.1-100 ?m
Medium vacuum1-10-31016-10131022-10190.1-100 mm
High vacuum10-3-10-71013-1091019-101510 cm-1 km
Ultra high vacuum10-7-10-12109-1041015-10101 km-105 km
Extremely high vacuum<10-12<104<1010>105 km

>From Wikipedia
The energy required to ionise hydrogen is about 40 electron-volts so for a
potential of ten volts over 4 cm (2500 V/m) a path of 16 cm is needed to
obtain a high enough energy to ionise the gas. That gives a pressure of 1E-4
mbar. At this pressure the free proton would have up to 2500 eV so the
temperature is 2.5 KeV. This is enough to cause a few fusion reactions and
with the exponential tail of the free path distribution energies of 100 KeV
or 3000 KeV would occur making proton-proton and D-D reactions possible.
Since these reactions increase the temperature this is expected to rapidly
rise. These potentials were reached in coil of the 10 volt oscillator.
For higher pressures such 3 Tor the mean free path is 100E-6m (=1E-4m) so
the potential would be 400 KV/m. This would be expected in a Tesla coil.
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