http://en.wikipedia.org/wiki/Fat_Man (C on diagram, below)
Now, it seems (and I say "it seems" because I haven't seen it documented
anywhere, yet) that the shape relies on the "reflection property" of the
hyperbola:
http://en.wikipedia.org/wiki/Hyperbola (section "Geometrical Properties")
The above property in optics, is equivalent to having a hyperbolic reflector and
a light source at the focus F1, whose imaginary image, based on the hyperbola's
reflection property, will be at F2 (inside the reflective hyperbola's wing).
F1 ------ < (Hyperbolic reflector) ---- F2.
The following reference:
http://misc.virtualcomposer2000.com/US4729318.pdf
solves the same problem, but instead of 2 foci, it creates a plane wave from a
single focus at the detonator. The shape given therein, is:
X = a0 + a1*sqrt(a2*(Y + a3)^2 + a4)
The above is a hyperbola:
(X - a0)/a1 = sqrt(a2*(Y + a3)^2 + a4) =>
[(X - a0)/a1]^2 - a2*(Y - (-a3))^2 = a4 =>
[(X - a0)/a1/sqrt(a4)]^2 - [(Y - (-a3))/(1/a2)/sqrt(a4)]^2 = 1
Questions: The refractive "dual" of a plane wave, using Snell's Law, would
require here a parabola, not a hyperbola, since after "focusing" the resultant
waves are plane waves. How come this case resolves to a hyperbola as well?
Is it possible to derive the two foci solution using Snell's Law?:
|----R1---|--|----------R2--------------|
F1 ------ <(*)------------------------- F2.
(*) Cone shaped Baratol
I.e., if the waves start at F1 and then meet the cone < which focuses them at
F2, how can I determine the shape of the surface <?
It seems to me that it should be a surface of revolution around the x-axis, with
the upper side (left) having the wanted shape and the lower side (right) being a
spherical surface of revolution of curvature R2. But the upper surface has me
stumped.
My guess is that the shape would also depend on the index of refraction n of the
Baratol cone:
n_{cone} = (Explosion speed of Comp B explosive)/(Explosion speed of Baratol)
Both speeds are known, hence n is known.
If anyone has any references or can derive the cone shape using Snell's Law
(which in principle *should* work even for blast waves) I'd appreciate the info.
Many thanks,
--
Ioannis
On the first glance I would rather see ellipsoids,
instead of hyperbolas,
did I miss something?
w.
--
Bob May
rmay at nethere.com
http: slash /nav.to slash bobmay
http: slash /bobmay dot astronomy.net
> For transmission work, the hyperbola is indeed the correct surface tho but I
> don't think that he's going to be putting the gasses through a lens system.
It is indeed a hyperola. I think I was able to solve the resultant differential
equation with Maple 9. See:
http://tinyurl.com/yazb3wh
--
Ioannis
> Remember that for this discussion, transmissions are pretty much imaginary!
Indeed. But note:
The solutions in the math posts are for the "reflective" case. Each "reflective"
case seems to have a "refractive" dual, which is obtained by "swapping" the
locations of the wings of the hyperbola.
Reflective:
F1-->---<--F2
Refractive:
F1--<--->--F2
It seems to me that a hyperbola opening towards (and close to F2, like that:
F1------<--F2
) will reflect waves from F1 in the radial direction opposite to F2 (creating an
imaginary image of F1 @ F2), but if you place the hyperbola at the position of
its dual "wing" (like that:
F1--<------F2 (*)
), and assume the contents of the hyperbola wing are transparent to whatever
waves are used, then it seems to me that the hyperbola will *focus* waves from
F1 onto F2.
For example, if the waves are light, then in (*) the entire hyperbola can
consist of glass, in which case it seems to me the glass will focus the light
source of F1 @ F2, with the image of F1@F2 being "real".
--
Ioannis