On Sun, 28 Oct 2012, Helmut Richter wrote:
> On Sat, 27 Oct 2012, William Elliot wrote:
> >
> > > > Let a and b be two positive integers such that ab + 1
> > > > divides a^2 + b^2.
> > >
> > > > Show that a^2 + b^2 divided by ab + 1 is a perfect square.
All variables are positive integers.
If p = ab + 1 | a^2 + b^2 and b = na, then n = a^2.
In addtion, if b = na and n = a^2, then p | a^2 + b^2 = pa^2.
> > Are there other examples for a and b for which p | a^2 + b^2 ?
>
> Here are some (a, b, p)
> 30 8 241
> 112 30 3361
...
> 81090 21728 1761923521
Computer generated?
> But the quotiont is a perfect square also in all these examples.
> I have some ideas how one could try to prove it but none of them makes for
> a complete proof.
>
What have you tried? I tried working with a and k = b - a > 0.