Newsgroups: sci.math
From: David W. Cantrell <DWCantr...@sigmaxi.net>
Date: 27 Sep 2007 17:38:10 GMT
Local: Thurs, Sep 27 2007 1:38 pm
Subject: Re: Finding Interest Rate without approximation or root-finding?
UKP <rockm...@gmail.com> wrote: Based on your sentence above, I'm guessing that you might be happy with a > How would you find Interest Rate *without approximation* from the > formula below..if the values for rest variables are given? > Is there any direct formula to calculate Interest Rate for such loan simple formula for the interest rate, even if it is not precise, because that would avoid your "troubles programming". So I will mention a formula I discovered a few years ago. I hadn't mentioned it in this newsgroup before because it had hoped to write an article comparing it with other such formulae in the literature... Anyway, for now, I'll just give the formula below and make a few comments. > The formula to find monthly payment is, MP = P*R / [(1-1/(1+R)^T))], Often, in practice, a way to find the interest rate is to use a series > where - > Monthly Payment= MP > P = principal (or loan amount) > Example to find Monthly Payment - > Principal = $250,000 expansion. But unfortunately, in the example above, that method fails. [For anyone interested, see the sci.math thread "A Series of Interest", started in Aug. 2004, at <http://groups.google.com/group/sci.math/browse_frm/thread/e5a502cd7bd...> and <http://groups.google.com/group/sci.math/browse_frm/thread/8cd003a0ddd...>. As mentioned in the latter part of the thread, the series converges if, using the OP's notation, T * MP < 2 * P. But that is not the case in the example above; the series diverges.] But there is a simple formula, which AFAIK has never appeared in the R = ((MP/P + 1)^(1/q) - 1)^q - 1 approximately (*) where q = lg(1 + 1/T), with lg denoting the binary logarithm. Example: Suppose that MP, the monthly payment, is $1419.47; P, the Using (*), q = lg(1 + 1/360) = ln(1 + 1/360)/ln(2) = 0.0040019... and then, approximately, R = (($1419.47/$250000 + 1)^(1/q) - 1)^q - 1 = 0.004558... = 0.4558...% For comparison, from the OP's example, we know that the precise interest Considering the simplicity of (*), it is reasonably accurate. More David W. Cantrell You must Sign in before you can post messages.
To post a message you must first join this group.
Please update your nickname on the subscription settings page before posting.
You do not have the permission required to post.
| ||||||||||||||