Account Options

  1. Sign in
The old Google Groups will be going away soon, but your browser is incompatible with the new version.
Google Groups Home
« Groups Home
Message from discussion Proposed Formal Definition of a Concrete Category
The group you are posting to is a Usenet group. Messages posted to this group will make your email address visible to anyone on the Internet.
Your reply message has not been sent.
Your post was successful
 
From:
To:
Cc:
Followup To:
Add Cc | Add Followup-to | Edit Subject
Subject:
Validation:
For verification purposes please type the characters you see in the picture below or the numbers you hear by clicking the accessibility icon. Listen and type the numbers you hear
 
Dan Christensen  
View profile  
 More options Oct 13 2012, 5:31 pm
Newsgroups: sci.logic, sci.math
From: Dan Christensen <Dan_Christen...@sympatico.ca>
Date: Sat, 13 Oct 2012 14:31:31 -0700 (PDT)
Local: Sat, Oct 13 2012 5:31 pm
Subject: Re: Proposed Formal Definition of a Concrete Category
On Oct 13, 4:13 pm, "Jesse F. Hughes" <je...@phiwumbda.org> wrote:

> Dan Christensen <Dan_Christen...@sympatico.ca> writes:
> > Interesting point, but isn't a morphism wrt to some property (or
> > structure) P just a transformation that preserves property P? That is
> > my intuitive sense of it. You cannot transform any set into its power
> > set since, in a transformation, one element is transforms into exactly
> > one other element. Can you then have morphism from a set to its power
> > set?

> The function f:N -> P(N) mapping n to {n} is a morphism in the category
> Set.

> So is the function g:N -> P(N) mapping n to N \ {n}.

> And the function mapping n to N.

> And the function mapping n to n u {0,...,47}.

> And so on.

> You see that *sets* of elements are elements of the powerset.  Thus, a
> function S -> P(S) takes elements of S to subsets of S -- because
> subsets of S *are* elements of P(S).

As I understand, a morphism on is a structure-preserving
transformation. I don't see the point of category theory otherwise.

Dan
Download my DC Proof 2.0 software at http://www.dcproof.com


 
You must Sign in before you can post messages.
To post a message you must first join this group.
Please update your nickname on the subscription settings page before posting.
You do not have the permission required to post.