Newsgroups: sci.math
From: "Ioannis" <morph...@olympus.mons>
Date: Wed, 11 Apr 2007 02:28:59 +0300
Local: Tues, Apr 10 2007 7:28 pm
Subject: Re: roots of x^12 = 2^x
"David W. Cantrell" <DWCantr...@sigmaxi.net> wrote in message
news:20070410190915.721$e0@newsreader.com... > Gerry Myerson <ge...@maths.mq.edi.ai.i2u4email> wrote: > > > "chapkovski" <chapkov...@gmail.com> wrote in message > > > > how many roots does this equation have? > > > Two real ones, approximately at x_0 ~= -.9467803304 and at x_1 ~= > > > x = -12*W((+/-) log(2)/12)/log(2) > > 2^x is smaller than x^{12} at x = -1, > Yes indeed. The two roots given by Ioannis are obtained using the principal > x = -12*W_{-1}(-log(2)/12)/log(2) > where W_{-1} denotes the -1 branch. solutions Maple provided to scan for real solutions, but I missed that one, which seems to be close to x_3 ~= 74.66932553 Moral of the story: When an equation is solvable exactly by W, *always* check > David -- I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/ You must Sign in before you can post messages.
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