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chapkovski  
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 More options Apr 10 2007, 4:24 pm
Newsgroups: sci.math
From: "chapkovski" <chapkov...@gmail.com>
Date: 10 Apr 2007 13:24:00 -0700
Subject: roots of x^12 = 2^x
how many roots does this equation have?

Thanks in advance for explaining


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smn  
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 More options Apr 10 2007, 4:56 pm
Newsgroups: sci.math
From: "smn" <smnewber...@comcast.net>
Date: 10 Apr 2007 13:56:45 -0700
Local: Tues, Apr 10 2007 4:56 pm
Subject: Re: roots of x^12 = 2^x
On Apr 10, 1:24 pm, "chapkovski" <chapkov...@gmail.com> wrote:

> how many roots does this equation have?

> Thanks in advance for explaining

For x<= 0  look at the function y=2^x-x^12 which is strictly
increasing from             -00 (atx= -00) to 1 at x=0 .Therefore
there is one root here.

for x>0 try to solve x^12/2^x=1 .take the natural logarithm(ln) to
reach the equivalent equation (lnx)/x=(ln2)/2 .The graph of y=(lnx)/x
is easily sketched from calculus from which you can read off the
number of roots.smn


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Ioannis  
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 More options Apr 10 2007, 5:09 pm
Newsgroups: sci.math
From: "Ioannis" <morph...@olympus.mons>
Date: Wed, 11 Apr 2007 00:09:35 +0300
Local: Tues, Apr 10 2007 5:09 pm
Subject: Re: roots of x^12 = 2^x
"chapkovski" <chapkov...@gmail.com> wrote in message

news:1176236640.212574.296720@a30g2000cwd.googlegroups.com...

> how many roots does this equation have?

Two real ones, approximately at x_0 ~= -.9467803304 and at x_1 ~= 1.063346831,
given by Lambert's W function as:

x = -12*W((+/-) log(2)/12)/log(2)

If you are looking for complex roots, there are more, given by more
complicated exressions in terms of the same function. Briefly, the equation
can be solved using Lambert's W function as follows:

x^12 = 2^x =>
x = (+/-) 2^(x/12) =>
(+/-) x*2^(-x/12) = 1 =>
(+/-) x*exp(-log(2)/12*x) = 1 =>
(+/-) -log(2)/12*x*exp(-log(2)/12*x) = -log(2)/12 =>
x = -12*W((+/-) log(2)/12)/log(2)

To learn more about Lambert's W function, Google it.

> Thanks in advance for explaining

--
I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/

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Gerry Myerson  
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 More options Apr 10 2007, 6:48 pm
Newsgroups: sci.math
From: Gerry Myerson <ge...@maths.mq.edi.ai.i2u4email>
Date: Tue, 10 Apr 2007 22:48:27 GMT
Local: Tues, Apr 10 2007 6:48 pm
Subject: Re: roots of x^12 = 2^x
In article <1176239376.759713@athprx04>,

 "Ioannis" <morph...@olympus.mons> wrote:
> "chapkovski" <chapkov...@gmail.com> wrote in message
> news:1176236640.212574.296720@a30g2000cwd.googlegroups.com...

> > how many roots does this equation have?

> Two real ones, approximately at x_0 ~= -.9467803304 and at x_1 ~= 1.063346831,
> given by Lambert's W function as:

> x = -12*W((+/-) log(2)/12)/log(2)

2^x is smaller than x^{12} at x = -1,
bigger at x = 0,
smaller at x = 2,
and bigger at x = 84 ( 2^{84} = (2^7)^{12} = 128^{12} > 84^{12} ),
so three real solutions.

--
Gerry Myerson (ge...@maths.mq.edi.ai) (i -> u for email)


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David W. Cantrell  
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 More options Apr 10 2007, 7:09 pm
Newsgroups: sci.math
From: David W. Cantrell <DWCantr...@sigmaxi.net>
Date: 10 Apr 2007 23:09:12 GMT
Local: Tues, Apr 10 2007 7:09 pm
Subject: Re: roots of x^12 = 2^x

Yes indeed. The two roots given by Ioannis are obtained using the principal
branch of the Lambert W function. The third root is given by

x = -12*W_{-1}(-log(2)/12)/log(2)

where W_{-1} denotes the -1 branch.

David


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Ioannis  
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 More options Apr 10 2007, 7:28 pm
Newsgroups: sci.math
From: "Ioannis" <morph...@olympus.mons>
Date: Wed, 11 Apr 2007 02:28:59 +0300
Local: Tues, Apr 10 2007 7:28 pm
Subject: Re: roots of x^12 = 2^x
"David W. Cantrell" <DWCantr...@sigmaxi.net> wrote in message
news:20070410190915.721$e0@newsreader.com...

Thanks to both for spotting the omission. I did an evalf(") on the exact
solutions Maple provided to scan for real solutions, but I missed that one,
which seems to be close to x_3 ~= 74.66932553

Moral of the story: When an equation is solvable exactly by W, *always* check
the -1 branch as well :-)

> David

--
I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/

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Phil Carmody  
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 More options Apr 11 2007, 9:26 am
Newsgroups: sci.math
From: Phil Carmody <thefatphil_demun...@yahoo.co.uk>
Date: 11 Apr 2007 16:26:51 +0300
Local: Wed, Apr 11 2007 9:26 am
Subject: Re: roots of x^12 = 2^x

Not at all. The moral of the story is to not wave great hefty tools
like Lambert W functions around when techniques that the average
10 year old should know provide more insight into the solution.

I am aghast that you seemed to think that x^12 would dominate 2^x
as x increased.

Phil
--
"Home taping is killing big business profits. We left this side blank
so you can help." -- Dead Kennedys, written upon the B-side of tapes of
/In God We Trust, Inc./.


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Ioannis  
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 More options Apr 11 2007, 11:07 am
Newsgroups: sci.math
From: "Ioannis" <morph...@olympus.mons>
Date: Wed, 11 Apr 2007 18:07:52 +0300
Local: Wed, Apr 11 2007 11:07 am
Subject: Re: roots of x^12 = 2^x
"Phil Carmody" <thefatphil_demun...@yahoo.co.uk> wrote in message

news:871wirca90.fsf@nonospaz.fatphil.org...
[snip]

> > Moral of the story: When an equation is solvable exactly by W, *always*
check
> > the -1 branch as well :-)

> Not at all. The moral of the story is to not wave great hefty tools
> like Lambert W functions around when techniques that the average
> 10 year old should know provide more insight into the solution.

Nah. I was just too bored to perform a full analysis of the equation.

> I am aghast that you seemed to think that x^12 would dominate 2^x
> as x increased.

It wasn't my fault. Honest :-) That was Maple V release 4's fault. To make
sure that I got the right behavior at +oo, I tried a quick:

> plot(x^12-2^x,x=-infinity..infinity);

Unfortunately, version V of Maple misbehaves on this graph, producing slightly
different variants each time. The time I checked, it produced a spike at +oo
for x->oo (erroneous), so I didn't check further. By breaking the domain of
the graph into smaller regions one can get the correct behavior, but I
stupidly relied on just that one glance I got from the -infinity..infinity
range, which was incorrect.

Shows the dangers of relying too much on CAS for analyses. Maybe we should ban
W altogether...

> Phil
> --

--
I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/

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Zdislav V. Kovarik  
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 More options Apr 11 2007, 12:20 pm
Newsgroups: sci.math
From: "Zdislav V. Kovarik" <kova...@mcmaster.ca>
Date: Wed, 11 Apr 2007 12:20:25 -0400
Local: Wed, Apr 11 2007 12:20 pm
Subject: Re: roots of x^12 = 2^x

On Tue, 10 Apr 2007, chapkovski wrote:
> how many roots does this equation have?

> Thanks in advance for explaining

Three real roots: look at the (real-variable) equivalent equation

 x^2 - 2^(x/6) = 0,

use repeatedly Rolle's Theorem to show that it cannot have more than
three roots, and use Intermediate Value Theorem to locate one root at a
time:

between (-1) and 0,
between 1 and 2,
and a large positive one because 2^(x/6) eventually outgrows x^2.
 (The location is: between 74 and 75).

Non-real roots: there are infinitely many of those because Lambert's
W-function has infinitely many branches, and on top of that, the twelfth
root function has 12 branches.

My computer equation solver found ten more non-real roots, in the strip
-1 < Re(x) < 1. But that is no promise that other roots will stay in that
strip - actually there is a root close to 121.55+111.31i.

Read about Lambert's W-function. The smaller of the positive roots was
found to be (log means the natural logarithm)

-12*lambertw(-1/12*log(2))/log(2).

I may have answered more than you required.

Cheers, ZVK(Slavek).


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Zdislav V. Kovarik  
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 More options Apr 11 2007, 12:24 pm
Newsgroups: sci.math
From: "Zdislav V. Kovarik" <kova...@mcmaster.ca>
Date: Wed, 11 Apr 2007 12:24:57 -0400
Local: Wed, Apr 11 2007 12:24 pm
Subject: Re: roots of x^12 = 2^x

On Wed, 11 Apr 2007, Ioannis wrote:
> "chapkovski" <chapkov...@gmail.com> wrote in message
> news:1176236640.212574.296720@a30g2000cwd.googlegroups.com...

> > how many roots does this equation have?

> Two real ones, approximately at x_0 ~= -.9467803304 and at x_1 ~= 1.063346831,
> given by Lambert's W function as:

> x = -12*W((+/-) log(2)/12)/log(2)

 Another real root, between 74 and 75, got missed:

-12*lambertw(-1,-1/12*log(2))/log(2)

Cheers, ZVK(Slavek)
[Nothing more added by me]


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Ioannis  
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 More options Apr 11 2007, 6:07 pm
Newsgroups: sci.math
From: "Ioannis" <morph...@olympus.mons>
Date: Thu, 12 Apr 2007 01:07:42 +0300
Local: Wed, Apr 11 2007 6:07 pm
Subject: Re: roots of x^12 = 2^x
"Ioannis" <morph...@olympus.mons> wrote in message

news:1176304073.615854@athnrd02...

> "Phil Carmody" <thefatphil_demun...@yahoo.co.uk> wrote in message
> news:871wirca90.fsf@nonospaz.fatphil.org...
> [snip]

[snip]

> > I am aghast that you seemed to think that x^12 would dominate 2^x
> > as x increased.

> It wasn't my fault. Honest :-) That was Maple V release 4's fault. To make
> sure that I got the right behavior at +oo, I tried a quick:

> > plot(x^12-2^x,x=-infinity..infinity);

> Unfortunately, version V of Maple misbehaves on this graph, producing
slightly
> different variants each time. The time I checked, it produced a spike at +oo
> for x->oo (erroneous), so I didn't check further. By breaking the domain of
> the graph into smaller regions one can get the correct behavior, but I
> stupidly relied on just that one glance I got from the -infinity..infinity
> range, which was incorrect.

And indeed, to further my defense for being a careless putz (8*(, here are the
two graphs:

>plot(x^12-2^x,x=-infinity..infinity);

Maple V release 4:
http://misc.virtualcomposer2000.com/graph1.gif

Maple 9:
http://misc.virtualcomposer2000.com/graph2.gif

The Maple V graph is clearly wrong. It's completely missing the third root.
That's the one I saw first and didn't even think twice about exp(x) > x^n,
which is an immediate givaway.

The Maple 9 graph also seems to be wrong, although "less wrong" than the Maple
V graph. I didn't check this one when I answered the question, but to me it
implies that the function reaches +infinity between the second and third root,
and that the third root is very large in magnitude, almost close to +infinity.

It would be nice to see the corresponding graph Maple 10 produces.
--
I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/


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Discussion subject changed to "Comprehensive Graphing (was: roots of x^12 = 2^x)" by David W. Cantrell
David W. Cantrell  
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 More options Apr 11 2007, 8:58 pm
Newsgroups: sci.math
From: Dav