please, is this true that:
if A(H) does not contain infinite dimensional closed spaces then Ais
a compact operator?
Yes. Hint: consider the spectral projection on (-infinity, -epsilon] union
[epsilon, infinity).
--
Robert Israel isr...@math.MyUniversitysInitials.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
thank you, Robert Israel