d P(t) / d t = P(t) Q, P(0)=I_{n}, Q \in R^{n x n}
where
q_{ij} >= 0 for i != j and q_{ii} = \sum_{i != j} (- q_{ij}).
The solution of this differential equation is the transition matrix
P(t) = exp( Q t )
of the Markov chain.
However, I have not seen the following definition where p(t) is a
stochastic vector:
d p(t) / d t = p(t) Q, p_0 \in R^n.
where p_0 is a stochastic vector whose positive components sum up to 1
which gives the initial probabilities for the Markov chain being in any
of the n states.
Is there any deeper reason why the matrix form is more common?
Thanks a lot!
Ivo