A set X of real numbers is nowhere dense if every nonempty open
interval in R contains a nonempty open subinterval disjoint from X.
Let X and Y be countable nowhere dense sets of non-negative real
numbers.
Let X+Y denote {x+y | x \in X and y\in Y}.
Is X+Y necessarily nowhere dense? If so, does this remain true if X
and Y are uncountable?
> (Suggested by a Putnam problem).
>
> A set X of real numbers is nowhere dense if every nonempty open
> interval in R contains a nonempty open subinterval disjoint from X.
>
> Let X and Y be countable nowhere dense sets of non-negative real
> numbers.
>
> Let X+Y denote {x+y | x \in X and y\in Y}.
>
> Is X+Y necessarily nowhere dense?
No. Counterexample suggested by the Cantor set...
Let X = Y = numbers in [0,1) with finite expansions base 3 with only
digits 0 and 2. Then X + Y is dense in [0,2].
> If so, does this remain true if X
> and Y are uncountable?
>
--
G. A. Edgar http://www.math.ohio-state.edu/~edgar/