On Oct 16, 4:48 pm, Jeffrey Angus <
grendel...@aim.com> wrote:
> Just a few abstract thoughts here. It makes sense to me,
> but then I've been known to over look the obvious on
> occasion. ;-)
>
> I have a solenoid coil that actuates a large 3-pole
> contactor. A short pulse to pull up on a lever that
> will toggle it from on position to another, and back.
>
> Making measurements of the solenoid coil, although
> potted in epoxy, yields a few measurements and a
> couple of guesses.
>
> <
http://www.pronine.ca/multind.htm>
>
> Coil form 1" diameter, 1-3/8" width and 1.5" depth.
> Going backwards on a solenoid coil java script, yields
> a matching 125 mH inductance (as measured) and 95 ohm
> DCR (as measured) for 2500 turns of #30 AWG which will
> fill the bobbin.
>
> This a 480 VAC actuator.
>
> Am I headed in the right direction if I assume the key
> factor here is ampere turns?
>
> Not allowing for the added inductance by a movable core,
> this has an impedance of roughly 100 ohms. So that works
> out to 4.8 amps or 12,000 ampere turns.
>
> Substituting 2000 turns of #28 AWG yields 80 mH, and 42
> Ohms. And subsequently roughly 12,000 ampere turns at
> 240 VAC.
>
> Putting 240 VAC across the 480 VAC coil yields only 6,000
> ampere turns and obviously is NOT enough to actuate the
> contactor transfer mechanism.
>
> The reason I'm curious is that ASCO seems to think that
> the replacement coil for this is worth $585, although
> they will sell it as the "sale price" of only $421.80.
>
> Jeff-1.0
> The other other one
>
> --
> "Everything from Crackers to Coffins"
Hi Jeff, I know nothing about power stuff or soleniod coils. I have
made a few open air magnetics. (Usually Helmholtz things) If the size
of both air coils is the same, then I believe your calculations are
correct. It's only the magnetic field strength that you need to match
and that's proportional to number of amp-turns. Wind away I say!
George H.