"Jamie" <
jamie_ka1lpa_not_v...@charter.net> wrote in message
news:gdsgr.53928$IQ1....@newsfe18.iad...
> I mean, most lasers have to be current regulated to some degree anyway,
> I would think if you have the current source at its max rating
> of the LD, capacitance wouldn't matter because you wouldn't have much
> control over that unless you plan on doing some sort of Peak and hold in
> which case, the peak condition will most likely vary with the diode.
There's no such thing as a current (or voltage) source at RF. The junction
has some resistance, even if it's just the (small, but certainly not
negligible) ideal diode resistance. Reality adds parasitic junction
resistance, wire bond and lead inductance, junction capacitance, etc.
At DC (or approximations thereof, i.e. up to frequencies where reactives can
be ignored for the circuit), one can build a current source, and simply not
care what voltage the load generates.
At RF, everything drives transmission lines and the speed of light applies,
so it's impossible to create a true current source. A "current source"
driving a TL generates a known voltage, dependent on the line's impedance.
When the energy reaches the load, the same voltage (in the line) divides
between the line and load impedances: to a first approximation, the line
becomes the source driving the load, not the source proper. It takes
several cycles of reflections, back and forth along the line, before source
and load are in agreement about what voltage and current stabilize at.
Therefore, it's much easier to simply match source and load, so that
although you need to know the RLC characteristics of each in order to do so
(matching networks and whatnot), you can simply transmit power into the
thing, and it gets modulated accordingly (in this case).
Tim
--
Deep Friar: a very philosophical monk.
Website:
http://webpages.charter.net/dawill/tmoranwms