On Sat, 28 Jan 2012 11:58:15 -0800, John Larkin
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There's no quibbling about the word "really", the quibble is about
your assertion that a diode junction is ohmic at vaguely described
qualitative "higher currents".
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>> and once you get past the knee -
>
>As noted, diodes don't have a "knee" unless you arbitrarily define
>one.
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"As noted"???
I don't really think an "arbitrary" definition is necessary, since the
location of the knee has been with us for decades.
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>where a relatively large
>>voltage change results in a small current change - the slope changes
>>so that for a relatively small increase in voltage you get a large
>>increase in current.
>
>No, that's backwards. Diodes, and LEDs, have current exponential on
>voltage at low currents. At higher currents, the contact and bulk
>resistivity start to dominate, and the voltage:current curve gets
>nearly linear.
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True enough, but "nearly linear" isn't quite the same as "ohmic", is
it?
And, it's just plain silly talk since it has very little to do with
what we're talking about, which is running LEDs from a voltage source.
Look at the V:I curve for a vanilla silicon diode at from zero volts
to where it lets, say, 1mA through the diode and you'll see that the
voltage across the diode, at that point, will be about 0.7V, mas o
menos.
Now run the voltage up to about 1.4V.
Will the current through the diode stop at 2mA?
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>Just look at the curves on real led data sheets. The smaller parts
>start to get ohmic at low currents, just a few mA. Bigger junctions
>will stay exponential at higher currents, because they have less bulk
>resistance.
>
>This is a really tiny junction, so the v/i curve is a straight line at
>operating currents:
>
>
http://vcclite.com/wp-content/files/VAOL-S8GT4-LED-0805-green.pdf
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Surely you can't be serious.
If you examine the Forward Current vs Forward Voltage curve with some
care, you'll find that with 10mA through the LED it drops about 1.9
volts, and with 20mA through it drops about 2 volts.
Simply using Ohm's law in both cases - in order to determine the
resistance of the LED in each case - yields for the first case:
E 1.9V
R = --- = ------- = 190 ohms
I 1e-2A
and for the second:
E 2.0V
R = --- = ------- = 100 ohms
I 2e-2A
then, since an ohmic load's resistance must be constant as the current
through it varies, that LED is clearly _not_ an ohmic load.
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Grasping at straws?
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JF