In form 1 g(x) evaluates the function g *exactly* once. It
decides the x>=0 is false (since it isn't *always* true), so
it returns f(-x) since and for all. That is, g(x) evaluates
to something completely different than g.
Does that make sense?
>
> P.S. I do not want to plot abs(x) function, that is only for example.
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> >
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--
William Stein
Associate Professor of Mathematics
University of Washington
http://wstein.org