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From: Colin Law <clan...@googlemail.com>
Date: Tue, 1 May 2012 21:28:31 +0100
Message-ID: <CAL=0gLvzLTx+FjcQd=WyvADDPhB=v=OiY0DhT_VEDft15GZ...@mail.gmail.com>
Subject: Re: [Rails] Setting an addional attribute on the join model in a
 has_many through relationship
To: rubyonrails-talk@googlegroups.com
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On 1 May 2012 17:05, Mohamad El-Husseini <husseini....@gmail.com> wrote:
> I have User, Account, and Role models. The Account model accepts nested
> properties for users. This way users can create their account and user
> records at the same time.
>
> class AccountsController < ApplicationController
> =C2=A0 def new
> =C2=A0 =C2=A0 @account =3D Account.new
> =C2=A0 =C2=A0 @user =3D @account.users.build
> =C2=A0 end
> end
>
> The above will work, but the=C2=A0user.roles.type=C2=A0defaults to=C2=A0m=
ember. At the time
> of registration, I needuser.roles.type=C2=A0to default to=C2=A0admin. Thi=
s does not
> work:
>
> class AccountsController < ApplicationController
> =C2=A0 def new
> =C2=A0 =C2=A0 @account =3D Account.new
> =C2=A0 =C2=A0 @role =3D @account.role.build
> =C2=A0 =C2=A0 # Role.type is protected; assign manually
> =C2=A0 =C2=A0 @role.type =3D "admin"
> =C2=A0 =C2=A0 @user =3D @account.users.build
> =C2=A0 end
> end

It depends what you mean by 'work'.  It will assign the type of @role
to "admin" but the problem is that you have not saved it to the
database after changing the type.  By the way, I advise against using
type as an attribute name, that is a reserved attribute name for use
with STI.

> ...

> # user_id, account_id, type [admin|moderator|member]
> class Role < ActiveRecord::Base
> =C2=A0 belongs_to :user
> =C2=A0 belongs_to :account
> =C2=A0 after_initialize :init
>
> =C2=A0 ROLES =3D %w[owner admin moderator member]
>
> =C2=A0 private
> =C2=A0 def init
> =C2=A0 =C2=A0 self.role =3D "member" if self.new_record?
> =C2=A0 end
> end

Should that not be self.type (apart from the fact that type is not a
good name)?  But if you want a default value for a column why not just
set the default in the database?

Colin