Newsgroups: rec.guns
From: Gunner Asch <gunnera...@gmail.com>
Date: Sat, 4 Jun 2011 09:35:14 +0000 (UTC)
Local: Sat, Jun 4 2011 5:35 am
Subject: Re: How Does A Claymore Mine Produce Shotgun Velocities
On Fri, 3 Jun 2011 10:38:03 +0000 (UTC), benevenutogiorno
# ##From the diagrams it looks like the detonators are blasting caps that #are inserted about 1/3 of the way from the edge of the plate inside #the explosive material. # #How the heck does this generate such velocities? There's no cartridge #casing to contain the explosion, there's no barrel and the whole #device is free to recoil backward (following Newton's Third Law: for #every action there's an equal and opposite reaction). Why is a _thin_ #plate sufficient? I would think a _heavy_ plate would be more #desirable. Claymore explosive is C4. C4 has a detonation velocity of 8,092 m/s (26,550 ft/s). http://www.youtube.com/watch?v=btNdSroBIns&feature=related You will note in the video..the wide area beyond the target..replay as #Is there something special about the dynamics of an explosion There are low order to high order explosives. C4 is a moderately high Gunner ----------------------------------------------------------------- You must Sign in before you can post messages.
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