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Message from discussion How Does A Claymore Mine Produce Shotgun Velocities

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More options Jun 4 2011, 5:35 am
Newsgroups: rec.guns
From: Gunner Asch <gunnera...@gmail.com>
Date: Sat, 4 Jun 2011 09:35:14 +0000 (UTC)
Local: Sat, Jun 4 2011 5:35 am
Subject: Re: How Does A Claymore Mine Produce Shotgun Velocities
On Fri, 3 Jun 2011 10:38:03 +0000 (UTC), benevenutogiorno

<benevenutogio...@yahoo.com> wrote:

#
##From the diagrams it looks like the detonators are blasting caps that
#are inserted about 1/3 of the way from the edge of the plate inside
#the explosive material.
#
#How the heck does this generate such velocities? There's no cartridge
#casing to contain the explosion, there's no barrel and the whole
#device is free to recoil backward (following Newton's Third Law: for
#every action there's an equal and opposite reaction). Why is a _thin_
#plate sufficient? I would think a _heavy_ plate would be more
#desirable.

Claymore explosive is C4.

C4 has a detonation velocity of 8,092 m/s (26,550 ft/s).

You will note in the video..the wide area beyond the target..replay as
necessary to note how the charge is focused by the thin steel plate and
spews the shot in a wide arc

#Is there something special about the dynamics of an explosion
#propagating along a metal plate? And why doesn't the metal plate need
#to be heavy? Can whatever's going on here be used to make a better
#shotgun?

There are low order to high order explosives. C4 is a moderately high
order explosive and the thin plate tends to focus the burn of the charge
from the back out to the front rather than in a 360' pattern.

Gunner

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