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Calvin's Knockout: BYO question
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Calvin
Feb 27, 2019, 10:50:23 PM2/27/19
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Hi all
In the absence of any questions of my own I'll run another KO quiz. This one does not have a theme, and will not be written by me. Rather, anyone who wishes to play must email me one question.
Questions can be on any topic but must have a numerical or date answer so that it is possible to eliminate the answer/poster that is furthest from being correct. I will write the first question, and then use the question from the eliminated person for each subsequent round. So no-one will be asked their own question. I reserve the right to edit or reject submitted questions.
I'll accept entries up until noon GMT on Monday, 4th March 2019. Send your question to 334152[at]gmail.com.
cheers,
calvin
In the absence of any questions of my own I'll run another KO quiz. This one does not have a theme, and will not be written by me. Rather, anyone who wishes to play must email me one question.
Questions can be on any topic but must have a numerical or date answer so that it is possible to eliminate the answer/poster that is furthest from being correct. I will write the first question, and then use the question from the eliminated person for each subsequent round. So no-one will be asked their own question. I reserve the right to edit or reject submitted questions.
I'll accept entries up until noon GMT on Monday, 4th March 2019. Send your question to 334152[at]gmail.com.
cheers,
calvin
Mark Brader
Feb 28, 2019, 3:14:51 AM2/28/19
to
"Calvin":
define "furthest from correct" in terms of ratios instead of differences.
Something to think about.
> I will write the first question,
I hope you have already done so.
> and then use the question from the eliminated person for each
> subsequent round. So no-one will be asked their own question.
And the winner's question will not be used!
> I reserve the right to edit or reject submitted questions.
If you reject a question, I suggest asking the entrant to submit another
one. I'm guessing you won't get more than about 7 entrants as it is.
In craps, the "shooter" rolls two dice. If you are betting on the
shooter, called a "pass" bet, then you win if the initial roll is
7 or 11; you lose if it is 2, 3, or 12. Otherwise the initial roll
becomes "the point" and the shooter continues rolling until either
the point is rolled again (in which case you win) or 7 is rolled
(in which case you lose).
Assuming that the dice are fair and no one is cheating, what is the
probability of winning? Answer with a decimal number from 0 to 1
or with a fraction in lowest terms.
Correct answer: 244/495, which is 0.49292929... (29 repeating).
--
Mark Brader, Toronto | "One thing that surprises you about this business
m...@vex.net | is the surprises." -- Tim Baker
My text in this article is in the public domain.
> Questions can be on any topic but must have a numerical or date answer
> so that it is possible to eliminate the answer/poster that is furthest
> from being correct.
If the question allows for a wide range of answers, it may be fairest to
> so that it is possible to eliminate the answer/poster that is furthest
> from being correct.
define "furthest from correct" in terms of ratios instead of differences.
Something to think about.
> I will write the first question,
> and then use the question from the eliminated person for each
> subsequent round. So no-one will be asked their own question.
> I reserve the right to edit or reject submitted questions.
one. I'm guessing you won't get more than about 7 entrants as it is.
In craps, the "shooter" rolls two dice. If you are betting on the
shooter, called a "pass" bet, then you win if the initial roll is
7 or 11; you lose if it is 2, 3, or 12. Otherwise the initial roll
becomes "the point" and the shooter continues rolling until either
the point is rolled again (in which case you win) or 7 is rolled
(in which case you lose).
Assuming that the dice are fair and no one is cheating, what is the
probability of winning? Answer with a decimal number from 0 to 1
or with a fraction in lowest terms.
Correct answer: 244/495, which is 0.49292929... (29 repeating).
--
Mark Brader, Toronto | "One thing that surprises you about this business
m...@vex.net | is the surprises." -- Tim Baker
My text in this article is in the public domain.
Mark Brader
Feb 28, 2019, 3:16:22 AM2/28/19
to
Mark Brader:
> In craps, the "shooter" rolls two dice...
Damn, that was meant to be emailed to Calvin!
Okay, here comes another question (in email) about something completely
different.
--
Mark Brader, Toronto, m...@vex.net | "Able was I ere I saw Panama."
> In craps, the "shooter" rolls two dice...
Damn, that was meant to be emailed to Calvin!
Okay, here comes another question (in email) about something completely
different.
--
Mark Brader, Toronto, m...@vex.net | "Able was I ere I saw Panama."
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