We all know that you can use a trick to quasi-self-contest Jimmy
Dunn. I am pretty sure that you can not do the same thing with Sonya
blue. Is it correct that you cannot self-contest Sonya Blue?
You cannot self-contest any card.
For crypt cards, though, you may be forced into that by consequence of
the transfers you make (which you are allowed to make, since transfers
do not put the card in play directly, in contrast to, say, playing a
second copy of a unique equipment you already have).
So you may put five counters on the uncontrolled Sonja, who will then
attempt to self-contest, with the result that the incoming copy is
burned (as per the rules on self-contesting [4.1])
http://groups.google.com/group/rec.games.trading-cards.jyhad/msg/7361e60b31498ba7
For such cards, you still handle the as-played bits, like Sonja's pool
gain.
http://groups.google.com/group/rec.games.trading-cards.jyhad/msg/cd912f43065fa72b
If you're asking if both copies of Sonja are removed from the game by
their special text, as in the case of two-Methuselah contesting, the
answer is no: the original copy is never contested in cases of self-
contesting (Sonja or otherwise). So the original copy stays.
Hm, is this a reversal of
http://groups.google.com/group/rec.games.trading-cards.jyhad/msg/46d91f309a98a642
?
No, it is not. The other is actual contestation, not self-
contestation.
Maybe I'm misreading it, but Scott's sentence reads - to me - that in
the case of two-Methuselah contesting, both copies of Sonja are
removed from the game by their special text, which is not what is
described in that link I gave.
No, just a simple error. As you note, not even two-Methuselah
contesting will result in both Sonjas self-removing.