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Message from discussion How should players be seeded at an elimination tournament

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More options Dec 2 1998, 3:00 am
Newsgroups: rec.games.backgammon
From: Elisabeth Scheicher <scheic...@xss.co.at>
Date: 1998/12/02
Subject: How should players be seeded at an elimination tournament
How should players be seeded at an elimination tournament?

Suppose we have eight players ranked from 1 to 8. In my mind there
are two plausible ways to seed them:

A:
B:

1-+                                     1-+
+---+                                   +---+
5-+   |                                 8-+   |
+---+                                   +---+
3-+   |   |                             4-+   |   |
+---+   |                               +---+   |
7-+       |                             5-+       |
+----                                   +----
2-+       |                             2-+       |
+---+   |                               +---+   |
6-+   |   |                             7-+   |   |
+---+                                   +---+
4-+   |                                 3-+   |
+---+                                   +---+
8-+                                     6-+

In (A) the difference of ranks is equal: in the first round
it's 4 = 5-1 = 7-3 = 6-2 = 8-4; if any player defeats the higher ranked
player then in the 2nd round it's 2  = 3-1 = 4-2 and in the final it's
1 = 2-1. The pairing in the first round is the same as in the Swiss
tournament system used in chess.

In (B) the sum of the ranks is equal: in the first round it's 9,
in the 2nd round it's 5 and in the final it's 3.

I think (A) should be preferred since ANY seeding favors the good and
(B)
goes a little bit too far in my mind.

Which of these two possibilities is used at backgammon (or e.g. tennis
tourneys)?