Newsgroups: rec.gambling.poker
From: e-reu...@uiuc.edu (Erik Reuter)
Date: 1997/04/07
Subject: Re: Going Too Far & Implicit Collusion
In article <JBURNS.97Apr7204...@wildcat.monmouth.com>, jbu...@monmouth.com (Jazbo Burns) wrote: It's not symmetrical since A gets all of C's outs if C folds, and B gets > There are three players A, B and C, having a, b and c outs on the > river, respectively. A has bet one unit, B has called and C must > decide whether or not to call with p units (including the bets of A > and B) in the pot. > p > p_c = (a+b)/c. > (a+c)p > a(p+1), or > Note that unless Player B or C has no outs (b=0 or c=0), p_a < p_c, so none of C's outs. B wants C to call, no matter what the pot size, since b(p+1) > b(p) > Morton's Theorem: Ignoring future betting rounds, there is always a pot This must be restated in light of the above. (SOME of the other players, > size such that the next player should fold to the bet according to > the Fundamental Theorem of Poker, yet the other players do not > want him to call (unless he has no outs). namely B, DO want him to call). Also, it isn't true head's up, since then b = 0 and p_c = p_a, but as stated above it isn't this isn't crystal clear. "If the best hand bets and is called by a drawing hand, there is a range I'm more interested in applications of the theorem to poker strategy. It -- You must Sign in before you can post messages.
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