thanks, I think ...
I used to do this ride at a conservative 12 MPH avg. speed (8 up, 16
down). I can't imagine holding an average speed of 24 miles an hour on a
course like this.
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Uh, if you averaged 8 MPH on the way up, and 16 MPH on the way down, you
certainly didn't average 12 MPH for the whole trip. Let's say that this
155 mile trip is exactly half uphill (77.5 mi) and half downhill. If
you average 8 MPH on the way up, it will have taken you 9.69 hours to go
up and 4.84 hours to go down, for a total time of 14.53 hours. Dividing
155 by 14.53 gives an average speed of 10.67 MPH. The faster you go,
the less time you have for your increased speed to affect your average.
Now, just for fun, if you averaged 10 MPH on the first half of a trip,
how fast do you have to go on the second half in order to average 20 MPH
for the entire trip?
Vavg = 155/(Tup + Tdown)
= 155/((77.5/Vup) + (77.5/Vdown))
= 2 Vup*Vdown/(Vup + Vdown)
or
(Vavg/Vup) = 2/(1 + (Vup/Vdown))
so right hand side cannot be greater than 2
for (Vup/Vdown) > 0 and for Vavg/Vup = 2 the only
possiblity is Vdown -> infinity
Which is impossible since no cyclists can exceed
the speed of light.
> Which is impossible since no cyclists can exceed
> the speed of light.
Hell - I don't even exceed the speed of dark.
A seven hour day for me takes me (and my tent and my other stuff) 140
km. I've rarely ever done it unloaded.
The summit is about half way. There's actually about a mile or two
difference, we'll fudge a bit, as I don't remember the exact distances).
It takes me about 9 hours (ride time) to reach the crest. It takes me
about 4 3/4 to get back down.
77 ÷ 9 = 8.5mph
77 ÷ 4.75 = 16.2mph
155 ÷ 13.75 = 11.3mph
OK, so I'm a little off :-3)
Five of our Club members did the GFC. With photos, it's at -
http://www.johnstone-wheelers.co.uk/mclean_ala.php