|
8
results for
In order to be stable, the masses of the three bodies must obey the formula
|
Introducing a third object into the Earth-Moon system
The mass of the object actually attempting to reside in the Trojan point must be
of negligible mass compared to the other two. In order to be stable, the masses
of the three bodies must obey the formula: 27*(m_1*m_2 + m_2*m_3 + m_3*m_1) < (
m_1 + m_2 + m_3)^2 If I did the arithmetic correctly, in a system where two ...
Jul 12 2004 by Dr John Stockton
- 67 messages - 25 authors
|
Introducing a third object into the Earth-Moon system
... in news:rec.arts.sf.science, Joseph Hertzlinger <jcyclespersecondlo ngisland
@nine.reticulatedcom.com> posted at Sun, 11 Jul 2004 17:35:20 : In order to be
stable, the masses of the three bodies must obey the formula: 27*(m_1*m_2 + m_2*
m_3 + m_3*m_1) < (m_1 + m_2 + m_3)^2 Have you a formula for N equal bodies? ...
Jul 13 2004 by Dr John Stockton
- 67 messages - 25 authors
|
Introducing a third object into the Earth-Moon system
... wrote: In order to be stable, the masses of the three bodies must obey the
formula: 27*(m_1*m_2 + m_2*m_3 + m_3*m_1) < (m_1 + m_2 + m_3)^2 If I did the
arithmetic correctly, in a system where two of the bodies have masses of 1 and 1
/81, the third must have a mass of either greater than 25.281 or less than 0.27.
...
Jul 11 2004 by pervect
- 67 messages - 25 authors
|
Introducing a third object into the Earth-Moon system
Erik Max Francis m...@alcyone.com rec arts sf science Joseph Hertzlinger wrote:
In order to be stable, the masses of the three bodies must obey the formula: 27*
(m_1*m_2 + m_2*m_3 + m_3*m_1) < (m_1 + m_2 + m_3)^2 If I did the arithmetic
correctly, in a system where two of the bodies have masses of 1 and 1/81, ...
Jul 11 2004 by Erik Max Francis
- 67 messages - 25 authors
|
3-body L4/L5 stability
Ilmari Karonen usen...@vyznev.invalid rec arts sf science sci astro
chornedsnork...@hushmail.com <chornedsnork...@hushmail.com> kirjoitti 19.09.2006
: Erik Max Francis wrote: chornedsnork...@hushmail.com wrote: In order to be
stable, the masses of the three bodies must obey the formula: 27*(m_1*m_2 + m_2*
m_3 + ...
Sep 24 2006 by Ilmari Karonen
- 10 messages - 4 authors
|
3-body L4/L5 stability
This does not prove absence of stable solutions for the unrestricted problem...
This is the article by Joseph Hertzlinger I was referring to: http://groups.
google.com/group/rec.arts.sf.science/msg/fed748de2c10622a Thanks! And it is: In
order to be stable, the masses of the three bodies must obey the formula: ...
Sep 18 2006 by chornedsnork...@hushmail.com
- 10 messages - 4 authors
|
3-body L4/L5 stability
chornedsnork...@hushmail.com rec arts sf science sci astro Erik Max Francis
wrote: chornedsnork...@hushmail.com wrote: In order to be stable, the masses of
the three bodies must obey the formula: 27*(m_1*m_2 + m_2*m_3 + m_3*m_1) < (m_1
+ m_2 + m_3)^2 Rearranging gives: 27 * [m_1*(m_2+m_3)+m_2*m_3]<[m_1+(m_2+m_3)]
...
Sep 19 2006 by chornedsnork...@hushmail.com
- 10 messages - 4 authors
|
3-body L4/L5 stability
Erik Max Francis m...@alcyone.com rec arts sf science sci astro chornedsnorkack@
hushmail.com wrote: In order to be stable, the masses of the three bodies must
obey the formula: 27*(m_1*m_2 + m_2*m_3 + m_3*m_1) < (m_1 + m_2 + m_3)^2
Rearranging gives: 27 * [m_1*(m_2+m_3)+m_2*m_3]<[m_1+(m_2+m_3)] ^2 So, no
constraints ...
Sep 18 2006 by Erik Max Francis
- 10 messages - 4 authors
|
|
|
|
