I am stuck with using regular expressions.
Imagine I have a vector of character strings like:
test <- c('filename_1_def.pdf', 'filename_2_abc.pdf')
How could I use regexpressions to extract only the 'def'/'abc' parts of these strings?
Some try from my side yielded no results:
testresults <- grep('(?<=filename_[[:digit:]]_).{1,3}(?=.pdf)', perl = TRUE, value = TRUE)
Somehow I seem to miss some important concept here. Until now I always used nested sub expressions like:
testresults <- sub('.pdf$', '', sub('^filename_[[:digit:]]_', '' , test))
but this tends to become cumbersome and I was wondering whether there is a more elegant way to do this?
Thanks for any help
Jannis
______________________________________________
R-h...@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Cheers!!
Albert-Jan
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
>________________________________
>From: Jannis <bt_j...@yahoo.de>
>To: r-h...@stat.math.ethz.ch
>Sent: Wednesday, October 5, 2011 1:56 PM
>Subject: [R] help with regexp
[[alternative HTML version deleted]]
test <- c('filename_1_def.pdf', 'filename_2_abc.pdf')
gsub(".*_([A-z]+)\\.pdf", "\\1", test)
hth.
--
Eik Vettorazzi
Institut für Medizinische Biometrie und Epidemiologie
Universitätsklinikum Hamburg-Eppendorf
Martinistr. 52
20246 Hamburg
T ++49/40/7410-58243
F ++49/40/7410-57790
--
Pflichtangaben gemäß Gesetz über elektronische Handelsregister und Genossenschaftsregister sowie das Unternehmensregister (EHUG):
Universitätsklinikum Hamburg-Eppendorf; Körperschaft des öffentlichen Rechts; Gerichtsstand: Hamburg
Vorstandsmitglieder: Prof. Dr. Guido Sauter (Vertreter des Vorsitzenden), Dr. Alexander Kirstein, Joachim Prölß, Prof. Dr. Dr. Uwe Koch-Gromus
Here are a couple of solutions:
# remove everything up to _b as well as everything from . onwards
gsub(".*_|[.].*", "", test)
# extract everything that is not a _ provided it is immediately followed by .
library(gsubfn)
strapply(test, "([^_]+)[.]", simplify = TRUE)
--
Statistics & Software Consulting
GKX Group, GKX Associates Inc.
tel: 1-877-GKX-GROUP
email: ggrothendieck at gmail.com
--- Gabor Grothendieck <ggroth...@gmail.com> schrieb am Mi, 5.10.2011: