http://screencast-o-matic.com/watch/cXljiXvlu
Forgive me for its crudeness
http://screencast-o-matic.com/watch/cXljiMvlw
Here I show why Zukes are stupid and demystify the 8/9.
http://screencast-o-matic.com/watch/cXljjdvlH
http://screencast-o-matic.com/watch/cXlj6JvIc
(I gonna look into this "screencast-o-matic" thingie....)
--JBw
----- Original Message -----
From: "dbkoski" <dbk...@comcast.net>
To: "R Buckminster Fuller Synergetic Geometry"
<r-buckminster-fuller...@googlegroups.com>
Sent: Thursday, December 08, 2011 5:24 AM
Subject: Re: Happy days are ahead (for me anyway)
> Phi scaling, vZome tidbit and a little history thrown in:
>
> http://screencast-o-matic.com/watch/cXlj6JvIc
[dels]
http://coffeeshopsnet.blogspot.com/2011/12/screen-test.html
There's a bit of your story (bio) as I don't want to lose site of the
fact that you're blue collaring it, paying bills with other work.
In the meantime, Harvard has failed to give front and center treatment
to the frontal Loeb it once had ("when Harvard had a brain" -- links
to Scarecrow thread we were following in Synergeo).
The size of the dunce cap over Washington DC is also phi-scaling by
the day, bigger than the Washington Monument already, for those who
can see.
Kirby Urner
Michael Jennings Chair of Computer Science
Holdenwebs / Open Bastion
Portland, Oregon 97214
PS: Chairman Steve got Antiprism working on this laptop. MacOS was
far less friendly, don't think he ever finished getting the
dependencies working on that one.
Re: I should be in bed, but I am really digging this program.
Nice link. I am tying to recall how I build the Zometool hub from a 2F
rhombic
triacontahedron. So, why not make a video?
http://screencast-o-matic.com/watch/cXlQe2vbW
Each shallow tetrahedron that caps an equilateral face is 3e3 + 1e6
Each shallow pentagonal pyramid that caps a pentagonal face is 11e3 +
3e6
20*(3e3 + 1e6) = 60e3 + 20e6
12*(11e3 + 3e6) = 132e3 + 36e6
(60e3 + 20e6) + (132e3 + 36e6) = 192e3 + 56e6
2F RT = 8*120E = 960E = 3840e3+ 960e6
(3840e3+ 960e6) - (192e3 - 56e6) = 3648e3 + 904e6 = 904E + 32e3
Volume of rhomicosidodecahedron with golden rectangles instead of
squares that
mimics the Zometool hub has a volume of 904E + 32e6, with a radius of
2.
--- In syne...@yahoogroups.com, "Alan M" <amichelson2002@...> wrote:
>
>
>
> http://tech.groups.yahoo.com/group/synergeo/message/40453
>
> --- In syne...@yahoogroups.com, "David" <dbkoski@> wrote:
> >
> > Phi scaling, v-Zome tidbits and a little history thrown in.
> >
> > http://screencast-o-matic.com/watch/cXlj6JvIc
> >
> > Warning 15 minutes long and I do not expect everyone to last through
> > the duration.
http://screencast-o-matic.com/watch/cXl6crv3a
On Dec 8, 10:13 pm, dbkoski <dbko...@comcast.net> wrote:
> This was first posted on Synergeo. I am seriously considering posting
> more here. Zubek related BS takes up a page or more per day and that
> dilutes the real information and many may miss out.
>
> Re: I should be in bed, but I am really digging this program.
>
> Nice link. I am tying to recall how I build the Zometool hub from a 2F
> rhombic
> triacontahedron. So, why not make a video?
>
> http://screencast-o-matic.com/watch/cXlQe2vbW
>
> Each shallow tetrahedron that caps an equilateral face is 3e3 + 1e6
> Each shallow pentagonal pyramid that caps a pentagonal face is 11e3 +
> 3e6
> 20*(3e3 + 1e6) = 60e3 + 20e6
> 12*(11e3 + 3e6) = 132e3 + 36e6
> (60e3 + 20e6) + (132e3 + 36e6) = 192e3 + 56e6
>
> 2F RT = 8*120E = 960E = 3840e3+ 960e6
> (3840e3+ 960e6) - (192e3 - 56e6) = 3648e3 + 904e6 = 904E + 32e3
>
> Volume of rhomicosidodecahedron with golden rectangles instead of
> squares that
> mimics the Zometool hub has a volume of 904E + 32e6, with a radius of
> 2.
>
> --- In syner...@yahoogroups.com, "Alan M" <amichelson2002@...> wrote:
>
>
>
> >http://tech.groups.yahoo.com/group/synergeo/message/40453
>
http://screencast-o-matic.com/watch/cXl6iAv0a
But you'd already done that same one earlier, when first constructing said T.
Vi Hart keeps her voice normal speed, but lets the video race quickly.
I think her technique involves adding the voice track later.
Your voice is clear, but then telling people you're in a rush for
company... makes it all pretty down home.
Hey, I was bragging about our visiting Wenninger again today, and
linking to these screen-o-matics from Mathfuture:
http://groups.google.com/group/mathfuture/browse_thread/thread/e5fb2c6971b2b61f
Kirby
I just started two days ago, so the learning curve is still steep. I
could pause more. I have a bunch of ideas. I could build up a
library of short videos and always improve them.
On Dec 10, 2:47 pm, kirby urner <kirby.ur...@gmail.com> wrote:
> This one is clear except you seemed rushed at the end and the last RT
> never really came together.
>
> But you'd already done that same one earlier, when first constructing said T.
>
> Vi Hart keeps her voice normal speed, but lets the video race quickly.
>
> I think her technique involves adding the voice track later.
>
> Your voice is clear, but then telling people you're in a rush for
> company... makes it all pretty down home.
>
> Hey, I was bragging about our visiting Wenninger again today, and
> linking to these screen-o-matics from Mathfuture:
>
> http://groups.google.com/group/mathfuture/browse_thread/thread/e5fb2c...
Depending on your intended audience, viewers have very short "persistence"
and attention span.
One will watch a 2 or 3 minute video (a 30 second one even more so), but
won't even trigger the "on" button for one he sees beforehand runs over 10
minutes. (That's "attention span")
And, if you pause for too long within, or seem to be poking pokeylike, the
viewer could well quit and go looking elsewhere. (That's "persistence",
which is related to the product's intensity, 'energy' and activity, hence to
"interest".)
--JBw
----- Original Message -----
From: "dbkoski" <dbk...@comcast.net>
To: "R Buckminster Fuller Synergetic Geometry"
<r-buckminster-fuller...@googlegroups.com>
Sent: Saturday, December 10, 2011 3:38 PM
Subject: Re: Happy days are ahead (for me anyway)
I was trying to give a bit of real time to the process of modeling,
which is less intimidating as final glossy packages are. The ones for
the ADD among us.
Another: FourthRITE
http://www.screencast-o-matic.com/watch/cXlQe2vbW
They are actually getting worse since I talk less, or have less to
say.
I have a new video, but I am seeing how many hits I get from the
polylist. Of course, I bcc'd Kirby and he probably has watched it.
Stay tuned.
The volumetric golden spiral
http://screencast-o-matic.com/watch/cXlXh4vt1
On Dec 11, 1:40 pm, dbkoski <dbko...@comcast.net> wrote:
> This video is my best achievement:
>
> The volumetric golden spiral
>
> http://screencast-o-matic.com/watch/cXlXh4vt1
>
> On Dec 10, 10:07 pm, dbkoski <dbko...@comcast.net> wrote:
>
>
I have watched these last three videos. It is awesome, but I have only
nibbled at it.
I need to lock it into an overall pattern. Well, the spiral is a great
pattern, no problem there.
But, the remainder tetrahedron, and the unresolvable tetrahedron in
the fat hexihedron in
the RT are more difficult to find a comprehension on one go.
dharmraj
the discovery of the spiral was a very fortunate combination of
knowledge of the remainder tet, the unresolved tet and the U module.
Those are the three tetrahedra that make the spiral. They are
increased linearly by phi. I may as well post my latest email to him
since it is a waste to sequester such information:
My response related to the golden sprial video.
Yes, I did say sqrt 2 + 2 and distinctly remember thinking sqrt5 + 2.
U module is not clear, this is where a break off possibility may be in
order.
This had to do with U mod, rem tet and unres tet. And negative
Fibonaci's
rem tet = 55E3 + 13E
unrs tet= 34E3 + 8E
Umod = 21E3+ 5E
rem tet = 13E3 + 3E
unrs tet = 8E3 + 2E
rem tet = 5E3 + 1E
unrs tet= 3E3 + 1E
Umod = 2E3+ 0E
rem tet = 1E3 + 1E
unrs tet = 1E3 + -1E
rem tet = 0E3 + 2E
unrs tet= 1E3 + -3E
Umod = -1E3+ 5E
rem tet = 2E3 + -8E
unrs tet = -3E3 + 13E
The U mod is the internal tetrahedon within the golden cuboid. Akin
to removing the (4) 1/8 octahedron from the Synergetics cube and
getting the regular tetrahedron. On the golden cuboid, removing the 4
regular T-module shapes or (120th of a rhombic triacontahedra).
The battle is real and ongoing. The command is weak and way to
"Ghandi like". I have burned my information at Synergeo and fanned
out to other fronts. Action is not something that should take yearly
increments and we must all be our own General.
I have had to take command and will clarify all that I can.
Thanks
>
> the discovery of the spiral was a very fortunate combination of
> knowledge of the remainder tet, the unresolved tet and the U module.
> Those are the three tetrahedra that make the spiral. They are
> increased linearly by phi. I may as well post my latest email to him
> since it is a waste to sequester such information:
>
Hi:
I am sitting in a coffee shop down town, evening. Just working
from memory getting
a mental picture formed.
I have a question. The fat hexehedron holds the unresolved tet,
the remainder, tet and the U module.
Now, that fat hexihedron, is it part of the rhombic triacontahedron? I
am thinking it is formed underneath
three rhombus's of the RT.
I am being a little lazy in asking a question when I could
probably go back through the videos and find it.
I learned a little about Fibonacci sequence in my short study of
programming, and saw it with the spiral
as you spoke of the next tet being the sum of the last two, or
something like that.
I am really intending to get back to some of my own studies, but
the direct exchange with another on
modelling creates its own enthusiasm.
dharmraj
On Dec 14, 5:52 am, dharmraj <dharm...@westnet.com.au> wrote:
> > the discovery of the spiral was a very fortunate combination of
> > knowledge of the remainder tet, the unresolved tet and the U module.
> > Those are the three tetrahedra that make the spiral. They are
> > increased linearly by phi. I may as well post my latest email to him
> > since it is a waste to sequester such information:
>
> Hi:
> I am sitting in a coffee shop down town, evening. Just working
> from memory getting
> a mental picture formed.
> I have a question. The fat hexehedron holds the unresolved tet,
> the remainder, tet and the U module.
The remainder tetrahedron is within the fat hexahedron. within the
remainder tetrahedron is another smaller remainder tetrahedron and the
unresolvable tetrahedron.
All three could be found depending on how fine of a resolution. At
even smaller levels everything shows up. I try to have things upsized
as much as possible.
> Now, that fat hexihedron, is it part of the rhombic triacontahedron? I
> am thinking it is formed underneath
> three rhombus's of the RT.
Yes, that is correct 20 fat hexahedron make the Unkelbach or rhombic
hexacontahedron or the "candle holder" shape that 12 RT nest in. One
could just nest 12 1/4 RT into the valleys and that makes an RT
itself.