shared projects for Beginners

[Kirill Zhdanov]

Hi there,
I read PPP by Stroustrup and found this group on his official site.
I try to understand what is mean shared project and how to work
together in team. So I published question on MSDN (search "shared
projects for Beginners" )but no effect.
Somone interested in team work for simple project?
We can discuss problem we need to solve and will try split it.
Please before writing message/answer insert "111" (like: "111? I want
to collaborate ...") that mean you interested in, else write anything
abstract or advice.
Thanks.

[Kirill Zhdanov]

[cipri_arad_77]

111 ! I whant to colaborate ... You can count on me with what I know.
Did you think at something for the project ? What we should do ?

[Adrian Mowrey]

There are plenty of open-source projects that you could contribute to. Try to search on Wikipedia.

--
You received this message because you are subscribed to the Google Groups "PPP-public" group.
To post to this group, send email to ppp-p...@googlegroups.com.
To unsubscribe from this group, send email to ppp-public+...@googlegroups.com.
For more options, visit this group at http://groups.google.com/group/ppp-public?hl=en.

--
Sincerely/Cu sinceritate,

Adrian Mowrey

[chief_1]

2 cipri_arab_77
ok, I just finished chapter 3 of PPP, and you?
So for first time I suggest just keep closer, maybe we can share some
files xxx.cpp for testing HOW It is share!? for example I solve
exercise 6 of chapter 3 myown way (I think so), I can share this file
to you for test.. look at this part of it:
<pre> /*
if(value1<=value2 &&
value2<=value3)
cout << value1<<", "<< value2 << ", " << value3<< endl;

else if ((value1<=value3)&&value3<=value2)
cout << value1<<", " << value3 <<", "<< value2 <<endl;

else if ((value2<=value1)&&value1<=value3)
cout << value2<<", " << value1 <<", "<< value3 <<endl;

else if ((value2<=value3)&&value3<=value1)
cout << value2<<", " << value3 <<", "<< value1 <<endl;

else if ((value3<=value1)&&value1<=value2)
cout << value3<<", " << value1 <<", "<< value2 <<endl;

else if (value3<=value2 && value2<=value1)
cout << value3<<", " << value2 <<", "<< value1 <<endl;
*/ </pre>
What is you solve for that exercise?
Do you study anything else (like html)?
See ya...

[cipri_arad_77]

I think that this post should have been on a separate thread, to leave
this one for a more complex project. Just an ideea.

Regarding that problem I do not find it on my archive of code written
by me.
But I will try to solve it now. Any way that style of solvong a
problem is something like very very very brute force :)
But is OK for now.
The ideea in programming as I found out after comparing my early
solutions to those of experienced programmers, seemed like comparing a
cottage with a modern car.
The ideea for this problem is to make an algorithm that will solve the
problem also for 4, 5 or 6, or more variables.
I think that you have solved all the combinations of those 3
variables, but what you will do if you have 26 variables ?
Or 2317659 variables ? Your algorithm will not work ...

Something that will work with any number of variables, and you will
learn in the future chapter (how to use vector) is like this :

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main()
{
vector<int> v;
int value;
while (cin >> value)
v.push_back(value);
sort (v.begin(),v.end());
for (int i=0; i<v.size(); ++i)
cout << v[i] << " , ";
}

Or if you whant to make your self a sorting algorithm and not use that
of the standard library, here is another sample of code :

#include <iostream>
#include <vector>
using namespace std;

int main()
{
vector<int> v;
int value;
while (cin >> value)
v.push_back(value);

// sorting algorithm for any number of integers
for (int i=0; i<v.size(); ++i)
for (int j=i+1; j<v.size(); ++j)
// if I found that a number is smaller then then a previous one I
switch them
if (v[j] < v[i]) {
int temp = v[i];
v[i] = v[j];
v[j] = temp;
}

// printing the integers sorted in ascending order
for (int i=0; i<v.size(); ++i) {
//if I am at the last integer, do not output any more commas, just a
newline
if (i == v.size()-1) {
cout << v[i] << endl;
break;
}
// otherwise output the integers folowed by commas
cout << v[i] << " , ";

[cipri_arad_77]

And of course an elegant solution of Bjarne Stroustrup :

http://www.stroustrup.com/Programming/Solutions/Ch3/e3-6.cpp

On 3 mar., 16:42, chief_1 <chiefkir...@gmail.com> wrote: