<The Planck's constant derived by the absolute power 10^100>, by Romano Amodeo

[amoram]

I have told that EVERY dimension of the Constants is always got from
the ABSOLUTE power 10^100. Also the numerical quantity 66,66666666
(only 10 numbers in all) is deduced by the power 10^100. Also the kg
equal to 10^-3 m^3.
We have 10^(400/6) x 10^35 kg = 10^66,66666666 x 10^35 x 10^-3 =
10^98,66666666 = 10^100 x 10^-1,33333334.
What is this 10^-1,33333334 ? It is 10^-1 x 10^0,33333333 x
10^0,00000001, in which 10^-1 gets 1 s^2, the exponent 1/3 gets a
cubic radix dividing the unit index of the electric masses in only one
of the 3 directions xyz of the 10^3 volume of the masses, and 10^-8 is
the mass unit model of the light absolute expansion 10^8. In the
complex, this 10^-1,33333334 transforms the kg in j s^2 (joule in
action in a plane sxs, transversal, because the index 100 is the plane
10x10).
So, to start from 10^100, for calculating all the energy, we have to
count in this order:

* 10^100 x 10^3 = 10^103. The absolute quantity 100, of the area
10x10, is counted in the 10^3 unitary masses contained in 1 m^3.
* 10^103 kg x 10^-1,33333334 = 10^101,66666666 J s^2. The quantity
in kg is counted in the J of the area s^2.
* 10^101,66666666 J s^2 = 10^66,66666666 x 10^35 J s^2. It keeps
out of the absolute quantity in J s^2 the absolute expansion 10^35 of
the positive quantity +5 of the 10 cycle, directed 5+7=35 in the 6
directions of the complex space and in the 1 direction of the time.
* 10^66,66666666 x 10^35 J s^2 = 66,66666666 x 10^35 J s^2. The
power 10^66,66666666 is counted in the energy of the exponent (which
counts the number of the times that the 10 cycle "strongly acts" the
combination to itself). This count happens through the division of the
power by 1 s, the unit of the time. This is so the TOTAL quantity
expressed in the absolutely minimal 10^35 units and in the linear way
of the mass energy.
* 66,66666666 x 10^-35 J s is the unitary quantity of 66,66666666
x 10^-35 J s and is the minimal energy of the Planck constant.

Why we have to consider only 8 decimal dimensions of 66,66666666?
Because only 10 numbers are those of the space. In the decimal
quantity, 10^-8 in the unitary dimension of the light. A smaller
quantity don't appear. The quantity of Planck in the minimal so that
what is under it appears only when it reach that quantity for the
eternal decimal inflation of the time unit that is 10^-1

Romano Amodeo