By theory, the "absolute c^2" is taken out of the 100 power

0 views
Skip to first unread message

amoram

unread,
Jun 25, 2008, 4:45:58 AM6/25/08
to physics science of RA

I derive directly the c^2 from the power (10^10)^10 = 10^100, that is
the "absolute quantity" present in the area xy 100, transversal of the
electromagnetic flow. This area at index 10x10 is counted in m^2.

(10^100)^1/4 m^2 = 10^25 m^2. So I have obtained, in 10^25 m^2,
the real presence 1/4 of the absolute 100%.
10^25 m^2 = 10^16 x 10^9 m^2. So I have noted, in 10^25 m^2, the
dimension 10^(2^4) how the "real charge worth".
10^9 x 10^16 m^2 = 9 x 10^6 m^2/s^2 = c^2. Since "power/s^2" is
"area of energy", I transform the "power" 10^9 in "area of energy"
dividing the mathematic power 10^9 for 1 s^2. The energy is only the
exponent 9 of the power. In this way 1.000.000.000, equal to 10^9,
assumes the Log quantity of the number 9, exponent of a power, that
numbers 1.000.000.000 as 9 times the cycle 10.
Reply all
Reply to author
Forward
0 new messages