AFAIR, I've seen in some Apocalypse that lexical scope boundaries will be  
the same as  boundaries of block, in which lexical variable was defined.

so, my question is, what the scope of variables, defined in C<if> and  
C<loop> conditions?

in perl5:

   my $a="first\n";
   if (my $a="second\n") {print $a}
   print $a;

prints

   second
   first

if I got it right, in perl6 same program will print

   second
   second

or will emit warning about redeclaring variable in the same scope..
sad. In C<if> case it isn't so significant, but what about C<loop>?

cite from Apocalypse4:
  ...
  The continue block changes its name to NEXT and moves inside the block it
  modifies, to work like POST blocks. Among other things, this allows NEXT
  blocks to refer to lexical variables declared within the loop, provided  
the
  NEXT block is place after them. The generalized loop:
     loop (EXPR1; EXPR2; EXPR3) { ... }
  can now be defined as equivalent to:
     EXPR1;
     while EXPR2 {
         NEXT { EXPR3 }
         ...
     }
  ...

so,

   loop (my $i=1;$i<10;$i++) { ... }

will declare $i for the rest of the block, in which loop is placed, won't  
it?

I feel that I will write things like:

   {loop (my $i=1;$i<10;$i++) {
       ...
   }}

But I really hope that I missed something important, stating that theese  
curlies are not necessary.