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argument from File or Command line ; LDAP
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ystole...@univ.haifa.ac.il  
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 More options Aug 3 2004, 4:39 am
Newsgroups: perl.ldap
From: ystole...@univ.haifa.ac.il
Date: Tue, 3 Aug 2004 10:39:59 +0200
Local: Tues, Aug 3 2004 4:39 am
Subject: argument from File or Command line ; LDAP
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I read from file

$line=<file> ;

chop($line);

and split :

($uid,$fname,$sname) = split(/\s+/,$line);

After call function of LDAP ,  receive endless loop in function of LDAP .

If I get variable $uid as argument from command line :

Prompt>>:     Program.pl uid

Then function of LDAP works OK !

Why ?

If I check variable $uid from command line and from file with function “cmp”, I receive 0 .

Help me, please.

JS.


 
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Chris Ridd  
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 More options Aug 3 2004, 4:00 am
Newsgroups: perl.ldap
From: chrisr...@mac.com (Chris Ridd)
Date: Tue, 03 Aug 2004 09:00:47 +0100
Local: Tues, Aug 3 2004 4:00 am
Subject: Re: argument from File or Command line ; LDAP
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On 3/8/04 9:39 am, ystole...@univ.haifa.ac.il <ystole...@univ.haifa.ac.il>
wrote:

Because the perl fairy makes it work.

> If I check variable $uid from command line and from file with function ³cmp²,
> I receive 0 .

> Help me, please.

Seriously ;-) you need to give us a bit more information - like your script
- to help identify the problem.

Cheers,

Chris


 
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