bugzilla ajax call ... i need some help

[uwe...@gmx.de]

hi ... im trying to get some bugs with an ajax-call:

==============================================================

var params = [{
/* The authentication parameters */
"Bugzilla_login": "user",
"Bugzilla_password": "pw",
/* The actual method parameters */
"ids": [1,2,3]
}];

var myObject = {
"method": "Bug.get",
"params": JSON.stringify(params)
};

$.ajax({"contentType": "application/json",
"data": myObject,
"crossDomain": "true",
"dataType": "jsonp",
"url": "http://localhost/jsonrpc.cgi",
"type": "GET",
success: function(bug){
alert("ok");

},
error: function () {
alert("no")
}
});

==============================================================

i created some bugs an when i just try this ajax call i get my "ok" popup.

BUT ... what i have to do, when i want to get more informations about the bug ... like creator or summary? its my first try with jquery/ajax so i dont know what i have to do with the return-value of my ajax-call.

thx for any idea, solution or other examples