Cypher output

[M.Alipour]

Hi,
I use this code in Cypher:

String qq="start n=node("+id+") match p=(n)-[?*]->(n) return p";
ExecutionEngine engine = new ExecutionEngine( graphDb );
ExecutionResult result = engine.execute(qq);
System.out.print("\n"+result.dumpToString());

and after running, i get:

+--------+
| p |
+--------+
| <null> |
+--------+
1 row, 1 ms

my problem: how can i handle returned value in this output? What is
the type of the Cypher output?Is table? Is string? or .... How i can
process Cypher output?
for example, i want this Pseudocode:

if output==Null then print "output is null"
if output=="myOutput" print "ok"

Thanks.

[Luanne Coutinho]

result.iterator() will give you an iterator of type Map<String,Object> where each map represents a "row"- the String is the column name and value is the column value (p in your case).
If you just want the results of a single column, you can do result.columnAs("p") which, in your case will give you an Iterator<Node>.

-Luanne

[Michael Hunger]

Please use parameters (for input variables) and reuse the execution-engine. (see: http://docs.neo4j.org/chunked/milestone/cypher-parameters.html)

You could have also found the basic usage in the manual: http://docs.neo4j.org/chunked/milestone/tutorials-cypher-java.html

Michael