On Thu, Oct 11, 2012 at 8:14 AM, Nikhanj <nikhan...@gmail.com> wrote:
> Hi
>     How to have an user defined step, returning a map.
>    I tried the below code

>    Gremlin.defineStep('fn1',[Vertex,Pipe],
>    {
> reltype,m->_().out(reltype).Name.groupCount(m).iterate();
>    });

>     m=[:];
>     g.v(2).fn1('Likes',m);

>     But i get class cast exception!!!

>     How to resolve this ???

> --

On Thursday, 11 October 2012 09:19:57 UTC-4, Stephen Mallette wrote:

> You are calling iterate() after groupCount and that is causing that
> error.  Removing it and simply accessing m after the gremlin has
> executed will allow you to get at the count.

> If you explicitly want to return the value of the groupCount to the
> next step, I guess you could define your step this way:

> Gremlin.defineStep('fn', [Vertex, Pipe], { x ->
>     _().out(x).name.groupCount.cap})

> and then do:

> gremlin> g = TinkerGraphFactory.createTinkerGraph()
> ==>tinkergraph[vertices:6 edges:6]
> gremlin> \. test.grm
> ==>null
> gremlin> m = g.v(1).fn('created').next()
> ==>lop=1
> gremlin> m
> ==>lop=1

> Does that help?

> Stephen

> On Thu, Oct 11, 2012 at 8:14 AM, Nikhanj <nikh...@gmail.com <javascript:>>
> wrote:
> > Hi
> >     How to have an user defined step, returning a map.
> >    I tried the below code

> >    Gremlin.defineStep('fn1',[Vertex,Pipe],
> >    {
> > reltype,m->_().out(reltype).Name.groupCount(m).iterate();
> >    });

> >     m=[:];
> >     g.v(2).fn1('Likes',m);

> >     But i get class cast exception!!!

> >     How to resolve this ???

> > --

On Mon, Oct 22, 2012 at 2:44 AM, Nikhanj <nikhan...@gmail.com> wrote:
> Hi,
>       When you perform  g = TinkerGraphFactory.createTinkerGraph()  , the
> database that you were pointing before would be lost as you are creating a
> new instance of g. How will we access the old database now ?? Can't it be
> achieved without using TinkerGraphFactory ??

> On Thursday, 11 October 2012 09:19:57 UTC-4, Stephen Mallette wrote:

>> You are calling iterate() after groupCount and that is causing that
>> error.  Removing it and simply accessing m after the gremlin has
>> executed will allow you to get at the count.

>> If you explicitly want to return the value of the groupCount to the
>> next step, I guess you could define your step this way:

>> Gremlin.defineStep('fn', [Vertex, Pipe], { x ->
>>     _().out(x).name.groupCount.cap})

>> and then do:

>> gremlin> g = TinkerGraphFactory.createTinkerGraph()
>> ==>tinkergraph[vertices:6 edges:6]
>> gremlin> \. test.grm
>> ==>null
>> gremlin> m = g.v(1).fn('created').next()
>> ==>lop=1
>> gremlin> m
>> ==>lop=1

>> Does that help?

>> Stephen

>> On Thu, Oct 11, 2012 at 8:14 AM, Nikhanj <nikh...@gmail.com> wrote:
>> > Hi
>> >     How to have an user defined step, returning a map.
>> >    I tried the below code

>> >    Gremlin.defineStep('fn1',[Vertex,Pipe],
>> >    {
>> > reltype,m->_().out(reltype).Name.groupCount(m).iterate();
>> >    });

>> >     m=[:];
>> >     g.v(2).fn1('Likes',m);

>> >     But i get class cast exception!!!

>> >     How to resolve this ???

>> > --

> --