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Alex  
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 More options Apr 18 2012, 2:31 am
From: Alex <alessio.battistu...@gmail.com>
Date: Tue, 17 Apr 2012 23:31:20 -0700 (PDT)
Local: Wed, Apr 18 2012 2:31 am
Subject: neo4jrest client question
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Hi guys, i use the neo4jrestclient api and looking documentation i
dont know how to visualize all relation
node to node, let me to explain ..

in the documentation i see u can search for incoming or outgoing
relation referred to a node

like this :

rels = node.relationships.incoming()

or

rels = node.relationships.outgoing()

but if i need all the relation referred to two nodes ?  like node1
referred to node2, is possible ?

thanks


 
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Nigel Small  
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 More options Apr 18 2012, 2:38 am
From: Nigel Small <ni...@nigelsmall.net>
Date: Wed, 18 Apr 2012 07:38:34 +0100
Local: Wed, Apr 18 2012 2:38 am
Subject: Re: [Neo4j] neo4jrest client question
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Hi Alex

I'm not sure exactly how you would do that from within the neo4jrestclient
specifically, but it's certainly possible via the REST interface. Py2neo
makes it available as below:

http://py2neo.org/doc/py2neo.html#py2neo.neo4j.Node.get_relationships

Nige

On 18 April 2012 07:31, Alex <alessio.battistu...@gmail.com> wrote:


 
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Alex  
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 More options Apr 18 2012, 2:44 am
From: Alex <alessio.battistu...@gmail.com>
Date: Tue, 17 Apr 2012 23:44:41 -0700 (PDT)
Local: Wed, Apr 18 2012 2:44 am
Subject: Re: neo4jrest client question
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Hi Nige,

im in search of something of that :

rels = node1.relationships.node2.<direction>

but dunno if this is done with traversal in more simple manner ..

Thanks

On 18 Apr, 08:38, Nigel Small <ni...@nigelsmall.net> wrote:


 
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James Thornton  
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 More options Apr 18 2012, 3:50 am
From: James Thornton <james.thorn...@gmail.com>
Date: Wed, 18 Apr 2012 00:50:02 -0700 (PDT)
Local: Wed, Apr 18 2012 3:50 am
Subject: Re: neo4jrest client question
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On Wednesday, April 18, 2012 1:44:41 AM UTC-5, Alex wrote:

> im in search of something of that :

> rels = node1.relationships.node2.<direction>

> but dunno if this is done with traversal in more simple manner ..

You can use a Gremlin script in Bulbs (http://bulbflow.com/) to find all
the relationships between nodes "a" and "b"...

>>> from bulbs.neo4jserver import Graph
>>> g = Graph()
>>> script = "g.v(a).bothE().filter{it.outVertex == g.v(b) || it.inVertex
== g.v(b)}"
>>> params = dict(a=1, b=2)
>>> edges = g.gremlin.query(script, params)

- James

 
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Alex  
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 More options Apr 18 2012, 5:37 am
From: Alex <alessio.battistu...@gmail.com>
Date: Wed, 18 Apr 2012 02:37:20 -0700 (PDT)
Local: Wed, Apr 18 2012 5:37 am
Subject: Re: neo4jrest client question
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Nice !

Ty James

On 18 Apr, 09:50, James Thornton <james.thorn...@gmail.com> wrote:


 
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Javier de la Rosa  
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 More options Apr 18 2012, 11:18 am
From: Javier de la Rosa <ver...@gmail.com>
Date: Wed, 18 Apr 2012 11:18:56 -0400
Local: Wed, Apr 18 2012 11:18 am
Subject: Re: [Neo4j] Re: neo4jrest client question
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Hi, Alex,

There is no way to do that in the neo4jrestclient, but you can use the
script Nigel has written also in the library:

>>> gremlin = gdb.extensions.GremlinPlugin.execute_script
>>> relationships = gremlin(script=script)

Or just returning the data as raw:

>>> relationships = gremlin(script=script, returns=client.constants.RAW)

Another less efficient way is just a comprehesion list like this one:

>>> [r for r in n2.relationships.all(type=["KNOWS"]).all() if n2 in [r.start, r.end]]

It returns all the relationships of types "KNOWS" between n1 and n2,
no matters the direction. Or you can even use traversals.

--
Javier de la Rosa
http://versae.es

 
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