Math 312: Foundations of Geometry

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Prop. 3.1: For any two points A and B: i. ->AB and ->BA = AB ii.->AB or ->BA = <->

1) a. What is the negation of [P or Q]? ~P&~Q b. What is the negation of [P and ~Q]? ~PorQ c.

*Revision* Proof: Given the point P,and the distinct non-collinear points A,B,C. By Prop. 2.2, <-