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Date: Fri, 10 Jul 2009 10:20:46 +0800
Subject: Re: auto submit a form, but there is a input[name="submit"] field...
From: WenDong Zhang <zwd2...@gmail.com>
To: Martin.Hon...@gmx.de
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yes, I did this.

form.action += (form.action.indexOf('?') == -1 ? '?' : '&') + 'submit=' +
form.submit.value;
form.submit.name = '__'; // rename
form.submit();

this works now, but the submit value is sent by GET method, if the backend
changes (such as php will receive the request value by $_POST, $_GET,
$_REQUEST), it may not get the submit's value.



On Thu, Jul 9, 2009 at 9:25 PM, Martin Honnen <mahotr...@yahoo.de> wrote:

> WenDong Zhang wrote:
>
>> Hi guys:
>>
>>  I've met a weird use case. there is a form, and I want to auto submit
>> when
>> the page loaded completed.
>> we can do it by FORM.SUBMIT()!  but, here I get a headache, there is a
>> input
>> field whose name is 'submit'...
>> so when I use form.submit(), there is a error : form.submit() is not a
>> function (of course form.submit is the input node...)
>>
>>    <form id="form1" action="/">
>>        <input type="text" name="submit" />
>>    </form>
>> <script type="text/javascript">
>>    var f = document.getElementById('form1');
>>    //console.log(f);
>>    //console.log(f.submit);
>>    f.submit();
>> </script>
>>
>>
>> so, I want to know is there another way to make the form auto submit
>>
>
> You will need to rename that input first.
>
> --
>
>        Martin Honnen
>        http://msmvps.com/blogs/martin_honnen/
> _______________________________________________
> dev-ajax mailing list
> dev-a...@lists.mozilla.org
> https://lists.mozilla.org/listinfo/dev-ajax
>



-- 
Best Regards!
Wen Dong