Variable inside function

[Tom]

Hello, good evening! I am with the following question ... Below is a
snippet of code:

What I need is to know how do I put the variable name "nome_procura"
within the search function.

I tried to put "+", "." .... and nothing works. If I leave the code as
it is, the function will look inside the tag "ALT" everything that has
name "nome_procura" and actually I wanted to appear "Mastercard",
where he came from a variable.

procura_string = 0;
$ (Doc). Find ('img'). Each (function () (
nome_procura var = "Mastercard";
procura_string = $ (this). attr ('alt'.) search (/ nome_procura / i);

Thanks,
Tom

[cc]

On 2010-08-31 20:03, Tom wrote:

Hello, good evening! I am with the following question ... Below is a
snippet of code:

What I need is to know how do I put the variable name "nome_procura"
within the search function.

I tried to put "+", "." .... and nothing works. If I leave the code as
it is, the function will look inside the tag "ALT" everything that has
name "nome_procura" and actually I wanted to appear "Mastercard",
where he came from a variable.

procura_string = 0;

Not sure what this line is for.

$ (Doc). Find ('img'). Each (function () (

Not
    $(document).find('img').each(function () {
?

nome_procura var = "Mastercard";

This line should be more like
    var nome_procura = "Mastercard";
(see syntax for var statement)

procura_string = $ (this). attr ('alt'.) search (/ nome_procura / i);

I don't really know jQuery, so I can't tell exactly what $(this) does (perhaps returns the jQuery-enhanced object for the `this` pointer?), but the rest of it can be suitably rearranged, perhaps as follows:
    var procura_string = $(this).attr('alt').search(new RegExp(nome_procura, "i"));
See the documentation on RegExp for some background, especially regarding the /pattern/ syntax, which treats whatever is inside the slashes as a regex character string (which is why it didn't access the variable's contents, but only used its name).

});

(Presumably you end the statement this way, although you didn't post this....)

-- 
cc | pseudonymous | <http://carlclark.mp/>

[Wes Kocher]

I think you have to use the RegExp() function:
http://bytes.com/topic/javascript/answers/94340-variable-inside-regex

Thanks,
Tom

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[Tom]

Hello ladies!

Thanks for helping me once again, it worked! I used the line:
procura_string = $ (this). attr ('alt'.) search (new RegExp
(nome_procura, "i"));

And just in case "nome_procura" is a variable that comes from an
external function.

Topic Done!

Thanks,
Regards,
Tom.