Received: by 10.180.91.231 with SMTP id ch7mr1235781wib.1.1350771345397; Sat, 20 Oct 2012 15:15:45 -0700 (PDT) X-BeenThere: midsouth-makers@googlegroups.com Received: by 10.180.90.134 with SMTP id bw6ls5993318wib.1.canary; Sat, 20 Oct 2012 15:15:43 -0700 (PDT) Received: by 10.181.12.101 with SMTP id ep5mr1593533wid.1.1350771343336; Sat, 20 Oct 2012 15:15:43 -0700 (PDT) Received: by 10.181.12.101 with SMTP id ep5mr1593532wid.1.1350771343328; Sat, 20 Oct 2012 15:15:43 -0700 (PDT) Return-Path: Received: from mail-we0-f180.google.com (mail-we0-f180.google.com [74.125.82.180]) by gmr-mx.google.com with ESMTPS id bu8si582615wib.2.2012.10.20.15.15.43 (version=TLSv1/SSLv3 cipher=OTHER); Sat, 20 Oct 2012 15:15:43 -0700 (PDT) Received-SPF: pass (google.com: domain of markturn...@gmail.com designates 74.125.82.180 as permitted sender) client-ip=74.125.82.180; Authentication-Results: gmr-mx.google.com; spf=pass (google.com: domain of markturn...@gmail.com designates 74.125.82.180 as permitted sender) smtp.mail=markturn...@gmail.com; dkim=pass header...@gmail.com Received: by mail-we0-f180.google.com with SMTP id t57so786644wey.11 for ; Sat, 20 Oct 2012 15:15:43 -0700 (PDT) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:from:date:message-id:subject:to :content-type; bh=e22R5TC73MKz69WquhLxv+6urfuqS5H9SQx1dKEiISY=; b=nmAAn1h3+sYpdxCRQZDEXyH32udutCuHZb5lf86sMoWu344s+ZnHE6ShE6LiN5z4u1 8HYZyTDV1JN3PlRrtj6MUPyfQCvpdkFeRfqawdBpC3jXM7vH2qIuv+6kFj592ab61ftz y9ZASO1+OKfRWKGGba2/E7+qa1AeRp1Yo1Sv6dthDsDWhmE5FOpD7drMxt1LB3TbtDOO FjgeR++hhBXEyA1VAyHIgv1AHSBbDmEItXFW1agHeaib1GA1TznMflxIrCzKwO1iud+J JYOGmRO5JWbPa9V6hYWtmM1Ux5LGXyJ32OywMruz/DCiMhPqjopwVbF/8IRKnyoxcwvC ApRg== Received: by 10.180.8.134 with SMTP id r6mr27129587wia.18.1350771343114; Sat, 20 Oct 2012 15:15:43 -0700 (PDT) MIME-Version: 1.0 Received: by 10.194.33.129 with HTTP; Sat, 20 Oct 2012 15:15:22 -0700 (PDT) In-Reply-To: <3efff22c-bf1f-4d74-b8c1-6ebd7ad8a1bd@googlegroups.com> References: <85bcecff-7b34-4cd4-9fa1-dd1cf1b45eb5@googlegroups.com> <3efff22c-bf1f-4d74-b8c1-6ebd7ad8a1bd@googlegroups.com> From: Mark Turnage Date: Sat, 20 Oct 2012 17:15:22 -0500 Message-ID: Subject: Re: [MidsouthMakers] Re: [#CodeMonkeys] Free Coursera course on Python To: midsouth-makers@googlegroups.com Content-Type: text/plain; charset=ISO-8859-1 It was fairly easy once I worked my brain around it. The trick is to look at all the difference between the two choice variables mod 5. You'll notice a definite pattern for the winning and losing matches. Just do a conditional based on that.