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How to get the current number of the first heading in a section ?
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Danny
Apr 2, 2009, 12:26:01 AM4/2/09
to
I have one sourcefile.
I create a new document every time that the header changes in my source
document. Afterwards, I copy the whole section to my new document.
So the end result is that I get as many result documents as there are
sections with "header changes" in my source document.
This works very fine.
I have one problem, the numbering of my headings starts every time again
from "1".
I want that in the new documents that the numbering stays the same as in the
original.
I know I can use "Startat"-property to set the beginning of mij numbered
list. But I can't find a way to get the correct number of the heading in my
source document. How can I do that?
I create a new document every time that the header changes in my source
document. Afterwards, I copy the whole section to my new document.
So the end result is that I get as many result documents as there are
sections with "header changes" in my source document.
This works very fine.
I have one problem, the numbering of my headings starts every time again
from "1".
I want that in the new documents that the numbering stays the same as in the
original.
I know I can use "Startat"-property to set the beginning of mij numbered
list. But I can't find a way to get the correct number of the heading in my
source document. How can I do that?
To explain my problem a little bit better, a short scheme:
Sourcefile:
<header1>
1. Heading1
1.1 Heading2
2. Heading1
<section-end new page>
<header2>
3. Heading1
3.1 Heading2
<section-end new page>
4 Heading1
......
My current result:
resultfile 1
1. Heading1
1.1 Heading2
2. Heading1
resultfile2
1. Heading1
1.1. Heading2
resultfile3
1. Heading1
Desired result
resultfile 1
1. Heading1
1.1. Heading2
2. Heading1
resultfile2
3. Heading1
3.1. Heading2
resultfile3
4. Heading1
Jean-Guy Marcil
May 14, 2009, 7:10:39 PM5/14/09
to
Danny was telling us:
Danny nous racontait que :
Danny nous racontait que :
Have you tried with something like:
MsgBox Selection.Range.ListFormat.ListString
???
--
______________________________
Jean-Guy Marcil
Montreal, Canada
Danny
Jul 7, 2009, 2:32:05 AM7/7/09
to
"Jean-Guy Marcil" wrote:
> It works! Thank you very much for the solution
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