How do I remove a line segment from a PathGeometry in wpf

[moondaddy]

I have a .net 3.0 wpf app and using c# I need to do 2 things:

1) Get the last point in the path, or get the last linesegment in the path
where I could then get the last point.

2) Remove the last linesegment in the path

How can I do this?

any comments would be great. Thanks!

--
moon...@newsgroup.nospam

[Peter Duniho]

On Thu, 01 May 2008 21:20:39 -0700, moondaddy <moon...@newsgroup.nospam>
wrote:

> I have a .net 3.0 wpf app and using c# I need to do 2 things:
>
> 1) Get the last point in the path, or get the last linesegment in the
> path
> where I could then get the last point.
>
> 2) Remove the last linesegment in the path
>
> How can I do this?

I'm just guessing, but looking at the docs (which is always a great place
to start when you have a question :) ), it looks to me as though you can
get a PathFigureCollection from your PathGeometry via the Figures
property. The collection offers the usual collection operations, such as
retrieving specific elements and adding or removing elements from the
collection.

Seems like that'd be a good place to start.

Pete

[Linda Liu[MSFT]]

Thank Pete for your reply!

Hi Moondaddy,

What Pete has suggested is correct. The following is a sample code snippet
to remove the last segment from a PathFigure.

private void button1_Click(object sender, RoutedEventArgs e)
{
PathGeometry pg = this.path1.Data as PathGeometry;
// remove the last segment from the first PathFigure within the
PathFigureCollection of the PathGeometry
pg.Figures[0].Segments.RemoveAt(pg.Figures[0].Segments.Count -
1);
}

Hope this helps.
If you have any question, please feel free to let me know.

Sincerely,
Linda Liu
Microsoft Online Community Support

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[moondaddy]

Thanks Linda that looks good. I see something I'm not familiar with.

Why do you use "as PathGeometry"? and not this:

PathGeometry pg = this.path1.Data;

Thanks again!

"Linda Liu[MSFT]" <v-l...@online.microsoft.com> wrote in message
news:AUzn9ZCr...@TK2MSFTNGHUB02.phx.gbl...

[Willy Denoyette [MVP]]

See your previous posting for a complete sample that illustrates how to draw
a rounded rectangle using PathGeometry.

Willy.

"moondaddy" <moon...@newsgroup.nospam> wrote in message
news:%23gsqC3C...@TK2MSFTNGP04.phx.gbl...

[Linda Liu[MSFT]]

Hi Moondaddy,

Thanks for your prompt reply!

The Path.Data property is of type Geometry, which is an abstract base
class.

In our scenario, the type of the path1.Data property is actually
PathGeometry, which is derived from the type Geometry. So I use the "as"
operator in C# to convert this property to the type PathGeometry.

Hope this helps.
If you have anything unclear, please feel free to let me know.

Sincerely,
Linda Liu
Microsoft Online Community Support

Delighting our customers is our #1 priority. We welcome your comments and
suggestions about how we can improve the support we provide to you. Please
feel free to let my manager know what you think of the level of service
provided. You can send feedback directly to my manager at:
msd...@microsoft.com.

This posting is provided "AS IS" with no warranties, and confers no rights.

[Linda Liu[MSFT]]

Hi Moondaddy,

I am reviewing this post in the newsgroup and would like to know the status
of this issue.

If you have any other question, please feel free to let me know.

Thank you for using our Managed Newsgroup Support Service!

[moondaddy]

Thanks for your explanation as it helps me understand what's going on. it
works now.

"Linda Liu[MSFT]" <v-l...@online.microsoft.com> wrote in message

news:9bT9AO%23rIH...@TK2MSFTNGHUB02.phx.gbl...

[Linda Liu[MSFT]]

Hi Moondaddy,

Thank you for your response!

If you have any other questions in the future, please don't hesitate to
contact us. It's always our pleasure to be of assistance.

Have a nice day!