Duvida com Strings. - Lua BR

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Message from discussion Duvida com Strings.
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Date: Wed, 4 Jul 2012 21:59:22 -0300
Message-ID: <CAE=v0fwJ_o-if0Prx8=n9qoO1YyBFybvg0oXzDixrpXjXMS...@mail.gmail.com>
Subject: Re: [lua-br] Duvida com Strings.
From: Eric Chiesse <echie...@gmail.com>
To: lua-br@googlegroups.com
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Eu costumo usar:

ini, fim, S1, S2 =3D string.find(S, "^(%w+)%s+(.-)")

---
Eric
br.linkedin.com/in/echiesse



Em 4 de julho de 2012 21:45, Luis Carvalho <lexcarva...@gmail.com> escreveu=
:

> > >A string em quest=E3o pode ser gigante, com v=E1rios espa=E7os, etc ..=
.
> > >Por=E9m quero sempre quebrar ela em duas na primeira ocorr=EAncia de u=
m
> espa=E7o,
> > >por exemplo se eu tivesse:
> > >
> > >S =3D "Andrws Aires Vieira"
> > >
> > >Preciso quebrar assim:
> > >
> > >S1 =3D "Andrws" e S2 =3D "Aires Vieira"
> >
> > Lua 5.1.4  Copyright (C) 1994-2008 Lua.org, PUC-Rio
> > >S =3D "Andrws Aires Vieira"
> > >S1, S2 =3D S:match"^(%S+) (.*)$"
> > >=3DS1
> > Andrws
> > >=3DS2
> > Aires Vieira
>
> So' lembrando que caso voce queira isolar todas as "palavras" da string
> inicial basta usar string.gmatch:
>
> Lua 5.1.4  Copyright (C) 1994-2008 Lua.org, PUC-Rio
> > s=3D"Andrws Aires Vieira"
> > for w in s:gmatch"(%S+)" do print(w) end
> Andrws
> Aires
> Vieira
>
> Acho que esse caso deve ser bem mais comum...
>
> Abracos,
> K
>
> --
> Computers are useless. They can only give you answers.
>                 -- Pablo Picasso
>
> --
> Luis Carvalho (Kozure)
> lua -e 'print((("lexcarva...@NO.gmail.SPAM.com"):gsub("(%u+%.)","")))'
>
> --
> Lua BR - http://groups.google.com/group/lua-br
>

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Eu costumo usar:<br><br>ini, fim, S1, S2 =3D string.find(S, &quot;^(%w+)%s+=
(.-)&quot;)<br><br clear=3D"all">---<br>Eric <br><a href=3D"http://br.linke=
din.com/in/echiesse" target=3D"_blank">br.linkedin.com/in/echiesse</a><br><=
br>
<br><br><div class=3D"gmail_quote">Em 4 de julho de 2012 21:45, Luis Carval=
ho <span dir=3D"ltr">&lt;<a href=3D"mailto:lexcarva...@gmail.com" target=3D=
"_blank">lexcarva...@gmail.com</a>&gt;</span> escreveu:<br><blockquote clas=
s=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;pad=
ding-left:1ex">
<div class=3D"im">&gt; &gt;A string em quest=E3o pode ser gigante, com v=E1=
rios espa=E7os, etc ...<br>
&gt; &gt;Por=E9m quero sempre quebrar ela em duas na primeira ocorr=EAncia =
de um espa=E7o,<br>
&gt; &gt;por exemplo se eu tivesse:<br>
&gt; &gt;<br>
&gt; &gt;S =3D &quot;Andrws Aires Vieira&quot;<br>
&gt; &gt;<br>
&gt; &gt;Preciso quebrar assim:<br>
&gt; &gt;<br>
&gt; &gt;S1 =3D &quot;Andrws&quot; e S2 =3D &quot;Aires Vieira&quot;<br>
&gt;<br>
&gt; Lua 5.1.4 =A0Copyright (C) 1994-2008 Lua.org, PUC-Rio<br>
&gt; &gt;S =3D &quot;Andrws Aires Vieira&quot;<br>
&gt; &gt;S1, S2 =3D S:match&quot;^(%S+) (.*)$&quot;<br>
&gt; &gt;=3DS1<br>
&gt; Andrws<br>
&gt; &gt;=3DS2<br>
&gt; Aires Vieira<br>
<br>
</div>So&#39; lembrando que caso voce queira isolar todas as &quot;palavras=
&quot; da string<br>
inicial basta usar string.gmatch:<br>
<div class=3D"im"><br>
Lua 5.1.4 =A0Copyright (C) 1994-2008 Lua.org, PUC-Rio<br>
</div>&gt; s=3D&quot;Andrws Aires Vieira&quot;<br>
&gt; for w in s:gmatch&quot;(%S+)&quot; do print(w) end<br>
Andrws<br>
Aires<br>
Vieira<br>
<br>
Acho que esse caso deve ser bem mais comum...<br>
<br>
Abracos,<br>
K<br>
<span class=3D"HOEnZb"><font color=3D"#888888"><br>
--<br>
Computers are useless. They can only give you answers.<br>
=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 -- Pablo Picasso<br>
<br>
--<br>
Luis Carvalho (Kozure)<br>
lua -e &#39;print(((&quot;<a href=3D"mailto:lexcarva...@NO.gmail.SPAM.com">=
lexcarva...@NO.gmail.SPAM.com</a>&quot;):gsub(&quot;(%u+%.)&quot;,&quot;&qu=
ot;)))&#39;<br>
</font></span><div class=3D"HOEnZb"><div class=3D"h5"><br>
--<br>
Lua BR - <a href=3D"http://groups.google.com/group/lua-br" target=3D"_blank=
">http://groups.google.com/group/lua-br</a><br>
</div></div></blockquote></div><br>

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