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Newsgroups: k12.ed.math
From:
"HoMoon115" <homoon... @yahoo.com>
Date: Tue, 04 Oct 2005 04:43:27 GMT
Local: Tues, Oct 4 2005 12:43 am
Subject: Help solving equation
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Newsgroups: k12.ed.math
From:
"ticbol" <tic... @yahoo.com>
Date: Tue, 11 Oct 2005 06:26:16 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
Sure it is possible, but L will be in terms of Q only.
Q = 10L - 1/2000 (L)squared
I assume the -1/2000 (L)squared is -(1/2000)(L^2) so that the given equation is quadratic only. [If it were -1/(2000 L^2), then the given equation would be cubic.]
Q = 10L -(1/2000)(L^2) Q = 10L -0.0005(L^2) Put them all to the lefthand side, 0.0005(L^2) -10L +Q = 0 Use the Quadratic Formula, L = {-(-10) +,-sqrt[(-10)^2 -4(0.0005)(Q)]} / (2* 0.0005) L = {10 +,-sqrt[100 -(0.002)Q]} / 0.001 L = 10,000 +,-1000sqrt[100 -0.002Q]
That means, L = 10,000 +1000sqrt[100 -0.002Q] ----*** or, L = 10,000 -1000sqrt[100 -0.002Q] ----***
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Newsgroups: k12.ed.math
From:
Duane Bozarth <dpboza... @swko.dot.net>
Date: Tue, 11 Oct 2005 06:26:18 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
HoMoon115 wrote:
> Q = 10L - 1/2000 (L)squared
> Is it possible to solve for L in this equation?
Q = 10L - 0.0005L^2 ?
If that's what you mean, ever hear of the quadratic formula?
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Newsgroups: k12.ed.math
From:
Duane Bozarth <dpboza... @swko.dot.net>
Date: Tue, 11 Oct 2005 06:26:19 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
HoMoon115 wrote:
> Q = 10L - 1/2000 (L)squared
> Is it possible to solve for L in this equation?
Perhaps second post,sorry...had more to add.
Ever hear of quadratic formula? (The old b and +/- sqrt(4ac) thingy...)
Yes in terms of Q but not numerically unless you select a value for Q. Otherwise, you have only one equation w/ two unknowns...
And, of course, there are limits on what Q can be if you wish to restrict the solution to the real line rather than the complex plane...
More about what you want/need would be helpful...
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Newsgroups: k12.ed.math
From:
Jeffrey Turner <jtur... @localnet.com>
Date: Tue, 11 Oct 2005 06:26:22 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
HoMoon115 wrote:
> Q = 10L - 1/2000 (L)squared
> Is it possible to solve for L in this equation?
Sure is. You now know how many Ls make a Q, how do you think
you'd find out how many Qs you'd need for an L?
--Jeff
-- But I venture the challenging statement that if American democracy ceases to move forward as a living force, seeking day and night by peaceful means to better the lot of our citizens, then Fascism and Communism, aided, unconsciously perhaps, by old-line Tory Republicanism, will grow in strength in our land. --Franklin Delano Roosevelt
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Newsgroups: k12.ed.math
From:
Kevin Karplus <karp... @cheep.cse.ucsc.edu>
Date: Tue, 11 Oct 2005 06:26:24 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
On 2005-10-04, HoMoon115 <homoon... @yahoo.com> wrote:
> Q = 10L - 1/2000 (L)squared
> Is it possible to solve for L in this equation?
Yes.
Assuming that the equation you meant to write was Q = 10 L - (1/2000) L^2 , this is a standard quadratic formula and can be solved with any of the techniques taught in Algebra 1 for solving quadratics.
------------------------------------------------------------ Kevin Karplus karp... @soe.ucsc.edu http://www.soe.ucsc.edu/~karplus Professor of Biomolecular Engineering, University of California, Santa Cruz Undergraduate and Graduate Director, Bioinformatics (Senior member, IEEE) (Board of Directors, ISCB) life member (LAB, Adventure Cycling, American Youth Hostels) Effective Cycling Instructor #218-ck (lapsed) Affiliations for identification only.
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Newsgroups: k12.ed.math
From:
MA Math Teacher <ma_ma... @hotmail.com>
Date: Tue, 11 Oct 2005 06:26:26 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
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Newsgroups: k12.ed.math
From:
Jim Spriggs <jim.spr... @ANTISPAMbtinternet.com.invalid>
Date: Tue, 11 Oct 2005 06:26:25 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
HoMoon115 wrote:
> Q = 10L - 1/2000 (L)squared
> Is it possible to solve for L in this equation?
L = 2000(5 +/- sqrt(25 + Q/2000))
-- I don't know who you are Sir, or where you come from, but you've done me a power of good.
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Newsgroups: k12.ed.math
From:
"ticbol" <tic... @yahoo.com>
Date: Tue, 11 Oct 2005 06:26:35 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation
Let me try answering this again. Looks like my answer 3 days ago would not be not posted.anymore.
Q = 10L -(1/2000)L^2 Q = 10L -0.0005L^2 0.0005L^2 -10L +Q = 0 Use the Quadratic Formula, L = {-(-10) +,-sqrt[(-10)^2 -4(0.0005)(Q)]} / (2*0.0005) L = {10 +,-sqrt[100 -0.002Q]} / 0.001 L = {10 +,-sqrt[100(1 -0.00002Q)]} / (1/1000) L = {10 +,-10sqrt[1 -0.00002Q]} * (1000) L = 10,000 [1 +,-sqrt(1 -0.00002Q)]
That is it.
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