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HoMoon115  
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 More options Oct 4 2005, 12:43 am
Newsgroups: k12.ed.math
From: "HoMoon115" <homoon...@yahoo.com>
Date: Tue, 04 Oct 2005 04:43:27 GMT
Local: Tues, Oct 4 2005 12:43 am
Subject: Help solving equation

Q  = 10L - 1/2000 (L)squared

Is it possible to solve for L in this equation?

Thanks,
Aaron

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ticbol  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: "ticbol" <tic...@yahoo.com>
Date: Tue, 11 Oct 2005 06:26:16 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

Sure it is possible, but L will be in terms of Q only.

Q  = 10L - 1/2000 (L)squared

I assume the -1/2000 (L)squared is -(1/2000)(L^2) so that the given
equation is quadratic only.
[If it were -1/(2000 L^2), then the given equation would be cubic.]

Q  = 10L -(1/2000)(L^2)
Q = 10L -0.0005(L^2)
Put them all to the lefthand side,
0.0005(L^2) -10L +Q = 0
Use the Quadratic Formula,
L = {-(-10) +,-sqrt[(-10)^2 -4(0.0005)(Q)]} / (2* 0.0005)
L = {10 +,-sqrt[100 -(0.002)Q]} / 0.001
L = 10,000 +,-1000sqrt[100 -0.002Q]

That means,
L = 10,000 +1000sqrt[100 -0.002Q]  ----***
or,
L = 10,000 -1000sqrt[100 -0.002Q]  ----***

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Duane Bozarth  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: Duane Bozarth <dpboza...@swko.dot.net>
Date: Tue, 11 Oct 2005 06:26:18 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

HoMoon115 wrote:

> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

Q = 10L - 0.0005L^2 ?

If that's what you mean, ever hear of the quadratic formula?

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Duane Bozarth  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: Duane Bozarth <dpboza...@swko.dot.net>
Date: Tue, 11 Oct 2005 06:26:19 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

HoMoon115 wrote:

> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

Perhaps second post,sorry...had more to add.

Ever hear of quadratic formula?  (The old b and +/- sqrt(4ac) thingy...)

Yes in terms of Q but not numerically unless you select a value for Q.
Otherwise, you have only one equation w/ two unknowns...

And, of course, there are limits on what Q can be if you wish to
restrict the solution to the real line rather than the complex plane...

More about what you want/need would be helpful...

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Jeffrey Turner  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: Jeffrey Turner <jtur...@localnet.com>
Date: Tue, 11 Oct 2005 06:26:22 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

HoMoon115 wrote:
> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

Sure is.  You now know how many Ls make a Q, how do you think
you'd find out how many Qs you'd need for an L?

--Jeff

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will grow in strength in our land.
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Kevin Karplus  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: Kevin Karplus <karp...@cheep.cse.ucsc.edu>
Date: Tue, 11 Oct 2005 06:26:24 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

On 2005-10-04, HoMoon115 <homoon...@yahoo.com> wrote:

> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

Yes.

Assuming that the equation you meant to write was
        Q = 10 L - (1/2000) L^2  ,
this is a standard quadratic formula and can be solved with any of the
techniques taught in Algebra 1 for solving quadratics.

------------------------------------------------------------
Kevin Karplus   karp...@soe.ucsc.edu    http://www.soe.ucsc.edu/~karplus
Professor of Biomolecular Engineering, University of California, Santa Cruz
Undergraduate and Graduate Director, Bioinformatics
(Senior member, IEEE)   (Board of Directors, ISCB)
life member (LAB, Adventure Cycling, American Youth Hostels)
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MA Math Teacher  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: MA Math Teacher <ma_ma...@hotmail.com>
Date: Tue, 11 Oct 2005 06:26:26 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

Yes.

HoMoon115 wrote:
> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

> Thanks,
> Aaron

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Jim Spriggs  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: Jim Spriggs <jim.spr...@ANTISPAMbtinternet.com.invalid>
Date: Tue, 11 Oct 2005 06:26:25 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

HoMoon115 wrote:

> Q  = 10L - 1/2000 (L)squared

> Is it possible to solve for L in this equation?

L = 2000(5 +/- sqrt(25 + Q/2000))

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ticbol  
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 More options Oct 11 2005, 2:26 am
Newsgroups: k12.ed.math
From: "ticbol" <tic...@yahoo.com>
Date: Tue, 11 Oct 2005 06:26:35 GMT
Local: Tues, Oct 11 2005 2:26 am
Subject: Re: Help solving equation

Let me try answering this again. Looks like my answer 3 days ago would
not be not posted.anymore.

Q = 10L -(1/2000)L^2
Q = 10L -0.0005L^2
0.0005L^2 -10L +Q = 0
Use the Quadratic Formula,
L = {-(-10) +,-sqrt[(-10)^2 -4(0.0005)(Q)]} / (2*0.0005)
L = {10 +,-sqrt[100 -0.002Q]} / 0.001
L = {10 +,-sqrt[100(1 -0.00002Q)]} / (1/1000)
L = {10 +,-10sqrt[1 -0.00002Q]} * (1000)
L = 10,000 [1 +,-sqrt(1 -0.00002Q)]

That is it.

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