how to set visible a node of a specific type

[Jonatan]

Hy there:
At the old version, i used the option visible to show some option of
the context menu only for some kind of types:
create : {
label : "Nuevo",
visible : function (NODE, TREE_OBJ) {
if(TREE_OBJ.get_type(NODE) == "N3") return -1;
},
But i can’t do the same on the new version:

"visible": function(obj,e) {
...
return -1;
}
And i can’t find it at new documentation.

Any help appreciated

Thanks!

[ChrisR]

Hi,

You can find here: http://www.jstree.com/documentation/contextmenu
information, that 'items' expects object or function. The function
receives right clicked node and should return object in format as
described in above docs.
The configuration might look like this:

contextmenu: {
items: function (NODE, TREE_OBJ) {
var obj = {};
if ('type1' == NODE.attr('rel')) {
obj['create'] = {
label: 'Create',
action: function() {/*...*/},
//...
}
}
if ('type2' == NODE.attr('rel')) {
obj['rename'] = {
label: 'Rename',
action: function() {/*...*/},
//...
}
}
if ('type2' == NODE.attr('rel') || 'type3' ==
NODE.attr('rel')) {
obj['some_other_action'] = {
label: 'Some other action',
action: function() {/*...*/},
//...
}
}
// etc.
}
return obj;
}

Best regards,
ChrisRaven

[vakata]

And also each of those items can have a property "_disabled" set to
true, which will render the item but it won't be clickable:

obj['rename'] = {
label: 'Rename',
action: function() {/*...*/},

_disabled : true,
//...
}

Kindest regards,
Ivan

[Niyak]

Just for completion: The function only gets passed one parameter NODE,
however the tree is accesible via "this" (TREE_OBJ = this).