mutually exclusive dependencies

[Dean Landolt]

I can't seem to figure out how to model mutually exclusive dependencies (either an object contains the "foo" prop or the "bar" prop, not both nor neither). I figure I'm missing something obvious. Any ideas?

[Gary Court]

You can use union types to do this:

{
"type" : [{
"properties" : {
"foo" : {}
},
"additionalProperties" : false
}, {
"properties" : {
"bar" : {}
},
"additionalProperties" : false
}]
}

-Gary

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[Dean Landolt]

On Fri, May 20, 2011 at 4:56 PM, Gary Court <gary....@gmail.com> wrote:

You can use union types to do this:

{
       "type" : [{
               "properties" : {
                       "foo" : {}
               },
               "additionalProperties" : false
       }, {
               "properties" : {
                       "bar" : {}
               },
               "additionalProperties" : false
       }]
}

Creative, but what if I have to also define other properties as well? It seems like this would be a relatively common case.

[Iain Duncan]

You could always use the extends (although a quick warning, if you look here there used to be a problem with extends and additionalProperties as it would validate both separately rather than combining so the validate assumes it is invalid as there are additional properties that come from the extends.  Apparently this has been fixed now but I'm not sure if the validators have caught up):

{
       "type" : [{
               "properties" : {
                       "foo" : {}
               },
               "extends": {
                       "id" : "common",
                       "properties" : {
                              "commonProp":{}

                       }
               },
               "additionalProperties" : false
       }, {
               "properties" : {
                       "bar" : {}
               },

               "extends" : { "$ref" : "common" },
               "additionalProperties" : false
       }]
}