From: Danny <d.wac...@prodigy.net>
Date: Thu, 13 Mar 2008 11:29:15 -0700 (PDT)
Local: Thurs, Mar 13 2008 2:29 pm
Subject: Re: $getJSON problem...demo works, but not my code?
jQuery replaces the '?' in the URL with a function name. Try the URL's
with something like 'callback=foo' in there; you'll notice that Flickr puts that name in the return as a function call (' foo( {..})') while your's still returns just [ {..} ]. And yes, using square brackets instead of parentheses will give an error if you use them in a function call On Mar 13, 9:33 am, "Andy Matthews" <li...@commadelimited.com> wrote:
> Danny...
> But when I view both URLs directly in the browser there appears to be no
> -----Original Message-----
> Behalf Of Danny
> Try going to the commadelimited.com URL directly in your browser. It looks
> So it looks like the problem is on the server side.
> Remember, jQuery uses JSONP by creating a <script> element and using the URL
> Danny
> On Mar 13, 6:51 am, Andy Matthews <andyandja...@gmail.com> wrote:
> > For my code it does nothing. No errors, but also no alert. It's almost
> >http://www.commadelimited.com/uploads/bullhorn/bullhorn.cfc?method=re...
> > On Mar 13, 6:35 am, MorningZ <morni...@gmail.com> wrote:
> > > When you say "get an error", what's the error?
> > > Do you use Firebug (http://www.getfirebug.com) at all to help? it's
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