Price of listing objects

[ykk]

Hi,

I understand that Google Storage provides some free queries.  I am interested in understanding how the queries is calculated when using gsutil.  This is because the bucket I am accessing has 1.5 million files!

When using sample code from 

http://code.google.com/apis/storage/docs/gspythonlibrary.html#listing-objects

uri = boto.storage_uri(DOGS_BUCKET, GOOGLE_STORAGE)
for obj in uri.get_bucket():
  print '%s://%s/%s' % (uri.scheme, uri.bucket_name, obj.name)
  print '  "%s"' % obj.get_contents_as_string()

If DOG_BUCKET has 100 items, does this code uses 101 queries, or just 1.  I understand gsutil ls gs://dog_bucket, uses one query.  How can I replicate that with the gsutil library?

Thanks in advance.

Regards

KK

[Jerjou Cheng]

Hello-

You can test for yourself how the code behaves if you like - just pass in the 'debug' parameter (set it to something greater than 0), and it will print out more information about each request. eg:

uri = boto.storage_url(DOGS_BUCKET, GOOGLE_STORAGE, debug=2)

In this case, the uri.get_bucket() call should correspond to a normal GET request on a bucket, and should only use one request, where the response includes the 100 items.

-Jerjou

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