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	<55fa8f7e-694e-4d34-8361-c40c1e2e1...@y41g2000yqm.googlegroups.com>
Date: Fri, 22 Jun 2012 18:23:10 -0700
Message-ID: <CAJW1onhW5JwNL9Jnjn+xe_Q3Ro=CvNg8nGBzy84-jSigGRR...@mail.gmail.com>
Subject: Re: [google-gson:1707]: Re: Default Value when deserialized?
From: Brandon Mintern <mint...@easyesi.com>
To: google-gson@googlegroups.com
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If your class has a default constructor (even an empty one), your
first pattern (initializing the instances variables where they are
defined instead of in the constructor) should work fine. If your class
does not have a default constructor, I believe (I could be wrong) that
Gson manually tries to allocate the object, which would skip any
initialization at all. This will actually fail on some platforms (I
have seen posts to that effect about Android allocations failing).

So you should always make sure Gson-constructed classes have a default
constructor. It may be that putting the code you showed in the default
constructor worked not because you moved the code around, but because
you had a default constructor at all.

On Fri, Jun 22, 2012 at 11:07 AM, shaunpatterson
<shaunpatter...@gmail.com> wrote:
> It seems adding
>
> public Test() {
> =A0 this.string1 =3D "default value";
> =A0 this.list1 =3D new ArrayList<String>();
> }
>
> seems to do the trick. =A0Is this the proper way of doing this?
>
> --
> Shaun
>
>
> On Jun 21, 12:04=A0pm, shaunpatterson <shaunpatter...@gmail.com> wrote:
>> I have an object defined like this:
>>
>> public class Test {
>> =A0 =A0 public String string1 =3D "";
>> =A0 =A0 public List<String> list1 =3D new ArrayList<String>();
>>
>> }
>>
>> And this object is built from the following JSON:
>>
>> { "string1" : "This is a test" }
>>
>> When deserialized, list1 is null. =A0Is there a way to have Gson ignore
>> missing values? =A0I want list1 to be an empty ArrayList if the value is=
 not
>> passed in the JSON.
>>
>> Thanks
>>
>> --
>> Shaun
>
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