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Is Stack Smashing Code standard?
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DK  
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 More options Jan 12 2007, 4:33 am
Newsgroups: gnu.gcc.help
From: "DK" <divyekap...@gmail.com>
Date: 12 Jan 2007 01:33:28 -0800
Local: Fri, Jan 12 2007 4:33 am
Subject: Is Stack Smashing Code standard?
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The following program gives the output as the last initialized variable
in the function func. Is this type of code behaviour standard or just a
gcc quirk?

#include <iostream>
using namespace std;
int func(int);
int main() {
   int n = func(2);
   cout << n << endl;
   return 0;

}

int func(int a) {
   int b = a*a;
   int c = b*b;

}

Output: 16
Thanks in advance.

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jacob navia  
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 More options Jan 12 2007, 6:25 am
Newsgroups: gnu.gcc.help
From: jacob navia <ja...@jacob.remcomp.fr>
Date: Fri, 12 Jan 2007 12:25:26 +0100
Local: Fri, Jan 12 2007 6:25 am
Subject: Re: Is Stack Smashing Code standard?
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DK a écrit :

This is undefined behavior. You fail to specify the return value.
Anything can happen, including (but not limited to)
returning the last value used.

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Paul Pluzhnikov  
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 More options Jan 12 2007, 9:52 am
Newsgroups: gnu.gcc.help
From: Paul Pluzhnikov <ppluzhnikov-...@charter.net>
Date: Fri, 12 Jan 2007 06:52:18 -0800
Local: Fri, Jan 12 2007 9:52 am
Subject: Re: Is Stack Smashing Code standard?
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jacob navia <ja...@jacob.remcomp.fr> writes:
> DK a écrit :
>> The following program gives the output as the last initialized variable
>> in the function func.

For some platforms and some versions of gcc and some compilation
options:

# Linux/x86
$ g++ -g junk.cc && ./a.out
16
$ g++ -g junk.cc -O && ./a.out
0

# Solaris/SPARC
$ g++ -g junk.cc  && ./a.out
16
$ g++ -g junk.cc -O && ./a.out
2

> Anything can happen, including (but not limited to)
> returning the last value used.

And (as above) anything *does* happen ...

Cheers,
--
In order to understand recursion you must first understand recursion.
Remove /-nsp/ for email.


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