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Description: Recreational Geometry Problems. (Moderated)
 

Geometry problem no.-8 
  Here is geometry problem no.-8:- Q.In a triangle ABC, AB=AC, point P is taken so that angle BPA=150 degree, angle PBC=30 degree and angle BAP=x degree. Find angle PCB.
By Sujeet Kumar  - Feb 1 2011 - 1 new of 1 message    

Three Points and a Circle 
  Yes that's the equation of the given circle passing through three given points, (x,y) (x1,y1) and (x2,y2).There are many [url=[link]]math websites[/url] to find more about circle geometry.
By Manjit Singh  - Jan 12 2011 - 1 new of 1 message    

2nd grade math worksheets 
  The main topics in grade 2 math can be writing numbers into numerals (standard form), in words and in expanded form up to ten thousands, rounding numbers, introduction to fractions and geometric shapes in two and three dimensions, simple addition and subtraction problems including easy word problems. [url=[link]]2nd grade math worksheets[/url] can be printed from many sites online free of cost.... more »
By Manjit Singh  - Jan 12 2011 - 1 new of 1 message    

Another compex geometry problem 
  Here is another complex geometry problem- Q.In a regular planar n-gon , 7 diagonals are concurrent at a point Q.Find least possible value of n.It is given that Q is not the center of the polygon. **Be wise, generalise.**
By Sujeet Kumar  - Jan 12 2011 - 5 new of 5 messages    

Very complex geometry problem 
  Here is very complex geometry problem- Q.In a regular n-gon , 8 diagonals are concurrent at a point M , which is not the center of the polygon. Find the all possible values of n. **You boil it in sawdust; you salt it in glue: You condense it with locusts and tape: Still keeping one principal object in view-... more »
By Sujeet Kumar  - Jan 10 2011 - 5 new of 5 messages    

Nothing special geometry problem 
  ...Here is the solution- Q.In a triangle ABC, point P is taken so that angle ABP=20 degree, angle PBC=40 degree, angle PCB=30 degree and angle PCA=10 degree.Find angle PAC. Sol.-Take a point M on AB , so that A is in the middle of M and B and triangle MBC is equilateral. Angle BAC=180-(20+40+30+10)=180-100= 80 degree.... more »
By Sujeet Kumar  - Jan 9 2011 - 1 new of 1 message    

Break 
  Following problem will give break from my boring problems- Q.Find the triangle of the least area which can cover any triangle with sides not exceeding 1. Above problem has just one connection with my previous problems.
By Sujeet Kumar  - Jan 9 2011 - 4 new of 4 messages    

One more boring geometry problem 
  Here is one more boring geometry problem- Q.In a triangle ABC , point P is taken so that ,angle ABP=20 degree, angle PBC=60 degree,angle PCB=40 degree and angle PCA=30 degree.Find angle BAP. When I(I think this is true for every one else) first started studying geometry , I encountered the problems which had nice angles such as 30, 45, 60 and 90 degrees.We had also exercises of construction of these angles.That time we had no idea of non-constructibles exercises or what is meaning of nonconstructible.I knew about Golden ratio much later, again this was related to 36 degree , which is again constructible.In fact , for me Langley Problem was first problem of its kind where angles such as 20 degree was used.I think this discrimination was because of nonconstructible nature of... more »
By Sujeet Kumar  - Jan 8 2011 - 1 new of 1 message    

Geometry problem no.-7 
  Here is geometry problem no.-7:- Q.In a triangle ABC , AB=BC, point P is taken inside the triangle so that BP=PC.It is given that angle PBC=x degree and angle PBA =( 60+x) degree.Find angle BAP.
By Sujeet Kumar  - Jan 7 2011 - 1 new of 1 message    

Geometry problem no.-6 
  Here is geometry problem no.-6:- Q.In a triangle ABC,point P is taken so that angle ABC=30 degree=angle PCB, angle PBC=x degree and angle PCA=(60-2x) degree.Find angle BAP. **Please! Please!! Please !!! Any body reply.Any comments, +ve or -ve .If I know I am doing something which is totally worthless, then I will stop.**... more »
By Sujeet Kumar  - Jan 6 2011 - 3 new of 3 messages    

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