Re: What is the area of black part?
João Pedro Afonso
gudi
> 31.5147?
May be link to a picture missing? I for one did not figure out the
problem.
Narasimham
João Pedro Afonso
> figure out the
> problem.
The picture appears to be resident in the Math Forum site... I have this feeling it is not going to appear in the newsgroup. But I think I can explain the problem: cut a circle in four equal parts, move or transport them in a way that they form a square with sides equal to radius (10). Each vertex will be a center to a circular sector or arc which will delimit an area in the center of the square. Find that area.
Philippe 92
>> May be link to a picture missing? I for one did not
>> figure out the problem.
>
> The picture appears to be resident in the Math Forum site...
No, it is available to be _downloaded_ from there, not directly
inside the message, but as an attachment.
> I have this feeling it is not going to appear in the newsgroup.
Of course as geometry.puzzle is a text only newsgroup on USENET !
Only the private part (in Drexel Math Forum) holds not even attached
pictures, but also the message itself that contains pictures, so that
seen from the newsgroup, you just answered a non existent message.
(original message by "Preeradech" doesn't even exist on USENET).
And as it is the custom here not to quote the message to which one
answers, the only hint to see what it is about is just your answer :
the numerical value answering an unknown question.
> But I think I can explain the problem:
> cut a circle in four equal parts, move or transport them in a way
> that they form a square with sides equal to radius (10).
> Each vertex will be a center to a circular sector or arc which will
> delimit an area in the center of the square. Find that area.
That would be a correct quote of the question, and should have been
mentioned at once inside your reply.
But IMHO most of posters here (Bill, Avni, ...) only see the forum
through the Drexel Web site, so that they just don't have any idea
of the difficulties others have with reading through USENET :
answers unrelated to questions, because broken references in messages
and no quoting at all.
As for the original problem, a hint is that each arc is divided
exactly in 3 by the others, resulting into some 30 degree angles.
Then sum/diffs of angular sectors and triangles gives the answer.
(I'm too lazzy to effectively do the calculation)
Regards.
--
Philippe Ch., mail : chephi...@free.fr
site : http://mathafou.free.fr/ (recreational mathematics)
João Pedro Afonso
> And as it is the custom here not to quote the message
> to which one
> answers, the only hint to see what it is about is
> just your answer :
> the numerical value answering an unknown question.
:-)
> > But I think I can explain the problem:
> > cut a circle in four equal parts, move or transport
> them in a way
> > that they form a square with sides equal to radius
> (10).
> > Each vertex will be a center to a circular sector
> or arc which will
> > delimit an area in the center of the square. Find
> that area.
>
> That would be a correct quote of the question, and
> should have been mentioned at once inside your reply.
Philippe, the original message was very plain: just a picture and a simple question about a black area in it. To quote it, wouldn't have solve nothing because of the needed picture. but that wasn't why I didn't. I was simply carried away. Narasimham message call me back to reality.
> But IMHO most of posters here (Bill, Avni, ...) only
> see the forum.
> through the Drexel Web site, so that they just don't
> have any idea of the difficulties others have with
> reading through USENET: answers unrelated to questions,
> because broken references in messages and no quoting
> at all.
And has a Usenet user, I should know that. Actually that was the reason why I start to come to the Drexel site but even so, I should strive to maintain the messages readable everywhere (even because I count with usenet to save them). But sometimes is easy to forget that.
Perhaps we should suggest to Drexel admins to start all replies with quoted text already inserted.
> As for the original problem, a hint is that each arc
> is divided
> exactly in 3 by the others, resulting into some 30
> degree angles.
> Then sum/diffs of angular sectors and triangles gives
> the answer.
> (I'm too lazzy to effectively do the calculation)
Well I was too lazy to write hints (it is easier to do the math and present a number). :-)
Cheers,
JPA